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    Strategies and techniques for approaching featured GMAT topics

The shape of a flower bed is a combination of semicircle and

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Manager
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Joined: 17 Jun 2015
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GMAT 1: 540 Q39 V26
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Re: The shape of a flower bed is a combination of semicircle and  [#permalink]

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New post 19 Dec 2015, 19:59
The perimeter of the rectangle is 28. But that does not clarfy the sides. IT could be 14 and 2 or 7 and 4. Statement 1 is insufficient

Length of diagonal is 10. L^2 + B^2 = 100
(A + B)^2 = A^2 + 2.A.B + B^2

Using this formula, we can deduce a length value that suffices the L>B requirement as well

Both together are sufficient
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Re: The shape of a flower bed is a combination of semicircle and  [#permalink]

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New post 20 Sep 2016, 07:39
C is the correct answer. Here's why:

(1) 2l + 2w = 28 --> INSUFFICIENT - we don't know the value of w or l; there are multiple combinations of l and w that could satisfy this equation if we were to guess

(2) w^2 + l^2 = 10^2 --> INSUFFICIENT - we don't know anything about the triangle itself or sides l and w

A,B,D eliminated...


Together - (1) + (2) - SUFFICIENT - We can combine (1) and (2) to isolate the value of l or w first and then solve for the remaining side.
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Re: The shape of a flower bed is a combination of semicircle and  [#permalink]

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New post 20 Sep 2016, 14:18
For DS problems and Geometry I always try to see if I can draw different shapes with the info given. If you can then it is insufficient. Statement two you can draw different shaped rectangles with diagonals 10. The degree of angles at which the diagonals will intersect will change the shape of the rectangle. So statement two is insufficient.

C is correct because now you have 2 different equations with 2 variables
Length = L and Width = W
Equation 1: 2L * 2W= 28
Equation 2: L^2 + W^2 = 100

And because the problem tells us which side is longer we can infer that the larger is the diameter of the semi-circle.
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Re: The shape of a flower bed is a combination of semicircle and  [#permalink]

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New post 24 Oct 2018, 14:20
1) 2l+2w=28

2) l^2+w^2=10^2

1)&2) (l+w)^2=l^2+w^2+2lw

196=100+2lw
96=2lw
48=lw

l= diameter
l=8, w=6 –> r=4

1/2*pi*r^2+2(l+w)=p

1/2*pi*16+2(6+8)=36pi
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Re: The shape of a flower bed is a combination of semicircle and &nbs [#permalink] 24 Oct 2018, 14:20

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