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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde [#permalink]

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17 Oct 2010, 00:17

The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is: a) 44 b) 62 c) 80 d) 86 e) none of these

A number will give a remainder only when it is greater than the multiple of the divisors. In such problems, always start with the greatest divisor. In our case 7.

Test each number with 7. We are left with 44 & 86. Now test 44 & 86 with 6. We are left with 44 & 86. Now test 44 & 86 with 4. We are left with 86.

Alternatively after testing with 7 we can easily see that 44 is a multiple of 4. So we only test 86 with the remaining options.

Hope this helps.
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Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde [#permalink]

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17 Oct 2010, 00:27

feruz77 wrote:

The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is: a) 44 b) 62 c) 80 d) 86 e) none of these

Pls, help with a solution method!?

Right, the solutions above are correct in their own way. But the way I think about this is the following :

The set of numbers that are divisible by numbers a,b,c are {LCM,LCMx2,LCMx3,...} So what we need to know is the LCM of 4,6,7 LCM of these numbers is 84.

So the smallest number leaving remainder 2 will be 86

Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde [#permalink]

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07 Dec 2016, 04:03

VeritasPrepKarishma wrote:

feruz77 wrote:

The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44 b) 62 c) 80 d) 86 e) none of these

Note that the smallest such number is 2. When 2 is divided by 4, the quotient is 0 and remainder is 2. Same logic for 6 and 7 too.

Out of the given options, the next smallest number will be LCM (4, 6, 7) + 2 = 86

Answer (D)

Dear Karishma

Thank you very much for your reply.

But why quotient should not be 0. The question asks about remainder not specifying the quotient. Why the whole number can not go into remainder without splitting into quotient and remainder? I can’t still get why 2 is not appropriate? Question asks about min number.

Re: The smallest number which, when divided by 4, 6 or 7 leaves a remainde [#permalink]

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07 Dec 2016, 09:53

Another way of looking at the problem, Going directly to the answer options, two answers can be omitted directly as they are divisible by 4 i.e. 44 and 80. We want the answer where after division from 4 remainder should be 2. For remaining two should comply the equation 4x+2, 6x+2 and 7x+2. The answer is 86. Answer D.

The smallest number which, when divided by 4, 6 or 7 leaves a remainde [#permalink]

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07 Dec 2016, 10:51

feruz77 wrote:

The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44 b) 62 c) 80 d) 86 e) none of these

Dear Prashantrchawla

Your approach is good and 86 definitely leaves remainder 2 when divided by 4, 6 and 7.

But, I have some doubts about this question. I think it’s trickier than it seems. The question does not ask which number from the list leaves remainder … or which smallest two digit number leaves remainder … or something of that sort. It simply and directly asks “what smallest number …” and smallest number is definitely 2 not 86.

But official answer says 86 so let it be. This will remain my personal dilemma .

The smallest number which, when divided by 4, 6 or 7 leaves a remainder of 2, is:

a) 44 b) 62 c) 80 d) 86 e) none of these

Note that the smallest such number is 2. When 2 is divided by 4, the quotient is 0 and remainder is 2. Same logic for 6 and 7 too.

Out of the given options, the next smallest number will be LCM (4, 6, 7) + 2 = 86

Answer (D)

Dear Karishma

Thank you very much for your reply.

But why quotient should not be 0. The question asks about remainder not specifying the quotient. Why the whole number can not go into remainder without splitting into quotient and remainder? I can’t still get why 2 is not appropriate? Question asks about min number.

Could you please elaborate.

Thank you in advance

The answer should be 2. The quotient can be 0. I said in my post above that the smallest such number is 2. The options don't have 2 and hence we needed to ignore it. Else, the correct answer is 2 only.
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