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# the sum of the intergers between 40 and 60?

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Manager
Joined: 29 Jul 2009
Posts: 176

Kudos [?]: 87 [0], given: 2

the sum of the intergers between 40 and 60? [#permalink]

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05 Oct 2009, 17:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Hi,

how can i find the sum of integers between 40 & 60?

thanks,

Kudos [?]: 87 [0], given: 2

Manager
Joined: 05 Jun 2009
Posts: 77

Kudos [?]: 3 [0], given: 1

Re: the sum of the intergers between 40 and 60? [#permalink]

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05 Oct 2009, 18:36
if its all inclusive 40 and 60, it is equal to the median * the numbers between 40 and 60 inclunsive so 50*21 =1050

Kudos [?]: 3 [0], given: 1

Manager
Joined: 25 Aug 2009
Posts: 163

Kudos [?]: 204 [0], given: 3

Location: Streamwood IL
Schools: Kellogg(Evening),Booth (Evening)
WE 1: 5 Years
Re: the sum of the intergers between 40 and 60? [#permalink]

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05 Oct 2009, 19:59
Good tech sfeiner!!

A more generic way to do it would be using the sum of an arithmetic progression -

n/2(2a +(n-1)*d)

where n is the total elements in the progression = 21
a = first term in the prog = 40
d = common difference in the Prog = 1

Applying to the formula 21/2(80+20) = 1050.
_________________

Rock On

Kudos [?]: 204 [0], given: 3

Manager
Joined: 06 Oct 2009
Posts: 68

Kudos [?]: 35 [0], given: 5

Re: the sum of the intergers between 40 and 60? [#permalink]

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06 Oct 2009, 02:40
Also...

sum=n(a+z)/2
where
n = number of terms
a = first term
z = last term

Applying here

Sum = 21(40+60)/2 = 1050

Kudos [?]: 35 [0], given: 5

Re: the sum of the intergers between 40 and 60?   [#permalink] 06 Oct 2009, 02:40
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# the sum of the intergers between 40 and 60?

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