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Math Expert V
Joined: 02 Sep 2009
Posts: 62499
The sum of three integers is 40. The largest integer is 3  [#permalink]

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12 00:00

Difficulty:   5% (low)

Question Stats: 86% (02:19) correct 14% (02:44) wrong based on 667 sessions

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The Official Guide For GMAT® Quantitative Review, 2ND Edition

The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

Problem Solving
Question: 62
Category: Algebra Simultaneous equations
Page: 69
Difficulty: 600

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Math Expert V
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Posts: 62499
Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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4
6
SOLUTION

The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

The middle number = x;
The largest integer is 3 times the middle integer = 3x;
The smallest integer is 23 less than the largest integer = 3x-23.

The sum of three integers is 40 --> x + 3x + 3x - 23 = 40 --> x=9 --> the product ((3x-23)*x*3x) is a multiple of 9. The only multiple of 9 among the options is B (9 + 7 + 2 = 18 = (a multiple of 9), which implies that 972 IS a multiple of 9).

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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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2
Set up the values as in the given question:

Let the middle value be denoted by the value 'n'. the sequence as per question is therefore:

3n-23;n;3n for the smallest, middle and largest integers respectively.
So 3n-23+n+3n=40
n=9.

After substitution, the value of the three numbers will be 4;9;27 in the same order above.

Their product =972.

Manager  Joined: 29 Apr 2012
Posts: 69
Location: United States
GMAT Date: 10-22-2012
Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Cosmas wrote:
Set up the values as in the given question:

Let the middle value be denoted by the value 'n'. the sequence as per question is therefore:

3n-23;n;3n for the smallest, middle and largest integers respectively.
So 3n-23+n+3n=40
n=9.

After substitution, the value of the three numbers will be 4;9;27 in the same order above.

Their product =972.

I did the same way.
Agree with B...
IMO:B
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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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2
1
Let us assume 3 different integers to be x, y and z, in ascending order.

Given that x + y + z = 40;
We are give that z = 3y & x = z - 23 (or) x = 3y - 23;(just to keep a single variable for calculation)

3y - 23 + y + 3y = 40;
7y = 63;
y = 9;

From here, we can determine that z = 27 & x = 4;

Since we are asked to find the product, we can find xyz: 4 * 9 * 27 = 972;

Ans is (B).
Manager  Joined: 20 Dec 2013
Posts: 220
Location: India
Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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1
a+b+c=40 (1)
Let a<b<c
Therefore,c=3b and a=c-23.
Replacing, a and b in (1)
we get c=27
a=4 and b=9
a*b*c=4*9*27=972
Ans. B
Intern  Joined: 06 Jan 2014
Posts: 35
Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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1
When you guys post questions from the Official Review...How do you know the difficulty level?

The difficulty is crazy low, but its a 600 Level Question? and yah, I got 972 as well

A+B+C=40

A+B+3B=40
3B-23+B+3B=40
7B=63

$$\frac{7B}{7}$$ $$=$$ $$\frac{63}{7}$$

$$B=9$$

The rest is history

I represent my three numbers as three different variables because it shows how they can be non or interrelated when I started the problem, I had no idea about the relationship(s) of the numbers and never assume they are "n" related, besides being integers.
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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

Let the numbers be $$x_1$$, $$x_2$$ and $$x_3$$

Given that, $$x_3 = 3*x_2$$ Or, $$x_2 = x_3/3$$ & $$x_1 = x_3 -23$$

Since,$$x_1+ x_2 + x_3 = 40$$

Or,$$x_3-23 +\frac{x_3}{3} + x_3=40$$

Or, $$3* x_3+x_3 + x_3*3=(40 + 23)*3$$

Or, $$7x_3=189$$

Or, $$x_3=27$$

Substituting the value of $$x_3$$, $$x_1= x_3-23=4$$ & $$x_2=x_3/3=9$$

So, $$x_1*x_2*x_3=4*9*27=972$$

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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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1
L + M + S = 40
3M + M + 3M - 23= 40
7M=63, M=9 -> L=27 -> S=4 ---> 4*27*9 ~ 100*9 = 900 (B)
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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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3
Hi All,

This prompt is built on a few Number Properties, so you can actually solve it with a bit of 'brute force' math (without the need of any lengthy equations or calculations:

We're given a few facts to work with:
1) The SUM of 3 integers is 40
2) The largest integer = 3(middle integer)
3) The largest integers = 23 + smallest integer

We're asked for the PRODUCT of the three integers.

First, notice how all 3 answers are POSITIVE, that means that our 3 integers are likely all positive. From the given information, we can see that the largest integer will be considerably bigger than each of the other two.

From the first fact, we know that the largest integer is 3 TIMES the middle integer, so the largest integer MUST be a multiple of 3. Here, we can start brute-forcing the work by 'playing around' with multiples of 3...

IF...
the largest number is 21, then the other two numbers are 7 and -2; the sum is 26, which is TOO LOW. Let's try something bigger....

IF....
the largest number is 24, then the other two numbers are 8 and 1; the sum is 33, which is TOO LOW. We have to go bigger...

IF....
the largest number is 27, then the other two numbers are 9 and 4; the sum IS 40, so these MUST be the 3 numbers

The answer to the question will be the product of 27, 9 and 4. You can organize this math in variety of ways, but you might find it easiest to look at it this way....

(27x4)(9) = (108)(9) --> something MORE than 900 but LESS than 1,000. You might also notice that since one of the numbers is 9, the product MUST be a multiple of 9 (and there's only one answer that fit's THAT description).

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GRE 1: Q169 V154 Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Here is my approach =>
let x,y,z be the three integers in decreasing order
here x+y+z=40
x+x/3+x-23=40
=> 7x=63*9=> x=27
so y=27/3=9
z=27-23=4
hence the product = 27*9*4
also as the only option that is a multiple of three is B => Smash it
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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

We can create the following 3 equations in which a = the smallest integer, b = the middle integer, and c = the largest integer:

a + b + c = 40

and

c = 3b

c/3 = b

and

c - 23 = a

Thus:

c - 23 + c/3 + c = 40

2c + c/3 = 63

Multiplying by 3, we have:

6c + c = 189

7c = 189

c = 27, so a = 27 - 23 = 4 and b = 27/3 = 9.

Thus, the product of the 3 integers is 4 x 9 x 27 = 972.

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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Bunuel wrote:
SOLUTION

The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

The middle number = x;
The largest integer is 3 times the middle integer = 3x;
The smallest integer is 23 less than the largest integer = 3x-23.

The sum of three integers is 40 --> x + 3x + 3x - 23 = 40 --> x=9 --> the product ((3x-23)*x*3x) is a multiple of 9. The only multiple of 9 among the options is B (9 + 7 + 2 = 18 = (a multiple of 9), which implies that 972 IS a multiple of 9).

Hi,

How do we know that the product ((3x-23)*x*3x) is a multiple of 9?

Doesn't the -23 mean that the product is whatever -23?
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Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Once you know that one of the three integers is 9 (in this case, that's the "middle number") which is a multiple of 9.... then the product of that number and two other INTEGERS will ALSO be a multiple of 9. While you're correct that the "-23" means that (3X - 23) is NOT a multiple of 9, that does not matter - again, since we're multiplying two integers by 9, the resulting product WILL be a multiple of 9.

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GMAT 1: 600 Q46 V27 Re: The sum of three integers is 40. The largest integer is 3  [#permalink]

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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

The sum of three integers is 40. The largest integer is 3 times the middle integer, and the smallest integer is 23 less than the largest integer. What is the product of the three integers?

(A) 1,104
(B) 972
(C) 672
(D) 294
(E) 192

x,y,z be the three numbers in increasing order.

z=3y
x=z-23
x=3y-23

x+y+z=40
3y-23+y+3y=40
y=9
z=27
x=4

Product of x,y, and z = 972

Option B.
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You are missing on great learning if you don't know what this is: Project SC Butler Re: The sum of three integers is 40. The largest integer is 3   [#permalink] 08 Feb 2020, 23:08
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