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Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers


6^2 does not equal 6, (see column 2, row 3). Can you elaborate?

If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!
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just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
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A faster way to solve this

All product = 6√6

A x B x √3 = 6√6, AB = (6√6 / √3)
C x D x 2√3 = 6√6, CD = (6√6 / 2√3)
A x B x C x D = (6√6 / 2√3) x (6√6 / √3) = (6 x 6 x 6) / ( 2 x 3) = 36

Don't solve for individual value, waste too much time
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daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
6^2 does not equal 6, (see column 2, row 3). Can you elaborate?
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The table above is a 3 by 3 grid of 9 numbers, 5 of which are given. The 4 numbers that are not given are denoted by A, B, C, and D. The product of the numbers in each row and in each column is the same for all rows and columns. What is the value of the product ABCD ?

From Second column we see that the multiplication for each row/columns should be \(= 6 * \sqrt{6}\)

\(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB * \sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(AB = 6 * \sqrt{2}\)

\(CD * 2\sqrt{3}\) \(= 2 * 3 * \sqrt{3} * \sqrt{2}\)

\(CD = 3 * \sqrt{2}\)

\(AB * CD = 6 * \sqrt{2} * 3 * \sqrt{2}\)

\(AB * CD = 18 * 2\)

\(AB * CD = 36\)

Hence, Answer is A
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Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.
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HarveyKlaus
Hi all,

Does anyone know where 6*sqrt(6) is coming from?

Thank you.

Refer to the center column that has numbers 1, 6 and sqrt(6). Multiply and you will get 6*sqrt(6).
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Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers
6^2 does not equal 6, (see column 2, row 3). Can you elaborate?


well, Im sorry I made a careless mistake, but you should get the point ;)


A 1 12
B 6 6
3 36 D
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pushpitkc
Smokeybear00
daviddaviddavid
just square each number in the table and then the solution becomes obvious


A 1 12
B 6 6
3 6 D


so we need 6*6=36

cheers


6^2 does not equal 6, (see column 2, row 3). Can you elaborate?

If you look at the question, the middle column reads 1,6,\(\sqrt{6}\) not 1,6,6
Hence squaring it will give you 1,36 and 6.

Btw, why are you squaring the numbers?

The solution to this problem is as follows :

Since the product of each of the rows and columns must be equal, only the center row has all three values,
the product of which is 6*\(\sqrt{6}\)

We need to find the product of A,B,C,D.

From the first row :
A * B * sqrt(3) = 6*sqrt(6) ==> A * B = 6 * sqrt(2)
From the third row :
C * D * 2sqrt(3) = 6*sqrt(6) ==> C * D = 3 * sqrt(2)

Therefore product of A,B,C and D as asked in the question is (6*sqrt(2))*(3*sqrt(2)) =6*3*2 = 36(Option A)

Hope it helps!

yes thanks, I made a careless mistake

I squared the numbers, because for me the problem becomes much easier
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