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# The table above shows the total sales recorded in July for

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The table above shows the total sales recorded in July for the 5 sales [#permalink]

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05 Dec 2008, 20:31
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Ann $450,000 Bob$360,000
Cal $190,000 Dot$210,000
Ed $680,000 The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was$330,000. What was the value of the incorrectly recorded sale?

A. $30,000 B.$48,000
C. $90,000 D.$120,000
E. $140,000 [Reveal] Spoiler: OA Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7368 Location: Pune, India Followers: 2281 Kudos [?]: 15074 [3] , given: 224 Re: The table above shows the total sales recorded in July for the 5 sales [#permalink] ### Show Tags 24 Jul 2011, 21:25 3 This post received KUDOS Expert's post 1 This post was BOOKMARKED snowbirdskier wrote: Ann$450,000
Bob $360,000 Cal$190,000
Dot $210,000 Ed$680,000

The table above shows the total sales recoreded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? (GMAT practice test) There are 5 values given to us and their median is 330 (Let's ignore the extra 0s). What does that mean? Say there is a list of numbers: 4, 6, 9, 12, 35 How do you get the median? It is the middle value in case you have odd number of values in increasing/decreasing order. It doesn't matter what the other values are. Median is equal to the value right in the middle. If median of a list of 5 values is 330, it means that 330 must be one of the 5 values. 2 values must be greater than 330 and 2 must be smaller than 330. Let me arrange the given list in decreasing order: Ann$450,000
Bob $360,000 Cal$190,000
Dot $210,000 Ed$680,000

680, 450, 360, 210, 190
I cannot touch the other 3 values (Just the red ones (Ann's and Cal's)). Since 680 and 360 remain and are greater than 330, so my actual list should look something like this:

680, 360, 330, ....., ..... (210 occupies one of these blanks)

The question now is: To whom does this 330 belong?

If Ann's sales decreases from 450 to 330, Cal's sale should increase by 120 (= 450 - 330) i.e. Cal's actual sales should be 190 + 120 = 310.
The list becomes: 680, 360, 330, 310, 210 - satisfies everything. The value of the incorrectly recorded sales must have been $120,000. Could 330 belong to Cal? Then Cal's sales would have increased by 330 - 190 = 140 Ann's sales would have decreased by 140 to get her actual sales of 310. But it is given that Ann's sales remains higher than Cal's. Hence this is not possible. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: The table above shows the total sales recorded in July for [#permalink]

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01 Feb 2012, 10:43
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Ann $450,000 Bob$360,000
Cal $190,000 Dot$210,000
Ed $680,000 The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was$330,000. What was the value of the incorrectly recorded sale?

A. $30,000 B.$48,000
C. $90,000 D.$120,000
E. $140,000 Old sales: {Cal=190, 210, 360, Ann=450, 680}. Now, the median of a set with odd # of terms is just the middle term (when ordered in ascending /descending order). So, old median=360. We know that new median=330 and Cal's sales are still less than Ann's, hence Ann's new sales must be 330 (Ann's sales # must be reduced so that it becomes the middle term: 360 and Ann must switch places): {210, Cal, Ann=330, 360, 680}. The value of the incorrectly recorded sale is Ann's old sales - Ann's new sales = 450 - 330 = 120. Answer: D. Hope it's clear. _________________ Intern Joined: 02 Oct 2010 Posts: 20 Schools: Ross,Duke,Emory Followers: 0 Kudos [?]: 3 [1] , given: 5 Re: Cal Sale [#permalink] ### Show Tags 29 Apr 2011, 09:06 1 This post received KUDOS A 4,50,000 B 3,60,000 C 1,90,000 D 2,10,000 E 6,80,000 Problem lies with sales of A & C...i.e. A' sales value 4,50,000 will have to be reduced by x and C's sales value will have to be increased by x. ( given in the problem ) After the correction/rearrangement the median value is 33,000 Keeping the other 3 sales values of B,D,E intact ?,2,10,000,3,30,000 (median),3,60,000,6,80,000 Two possibilities are there : 1.C's sales value of 1,90,000 would have been increased to 3,30,000..In that case, A's sales value becomes 3,10,000. This goes against the given information that A's sales is still higher than C. 2.So, we can conclude that A's sales value has been decreased to 3,30,000. Hence the incorrect value = 4,50,000 - 3,30,000 = 1,20,000 Hope I've made sense..Probably I've made it lengthy...!!! Verbal Forum Moderator Joined: 10 Oct 2012 Posts: 629 Followers: 83 Kudos [?]: 1191 [1] , given: 136 Re: The table above shows the total sales recorded in July for [#permalink] ### Show Tags 23 May 2013, 10:59 1 This post received KUDOS mydreammba wrote: Ann$450,000
Bob $360,000 Cal$190,000
Dot $210,000 Ed$680,000

The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A.$30,000
B. $48,000 C.$90,000
D. $120,000 E.$140,000

Let the transaction amount be x. Given that 450,000-x>190,000+x --> 2x<260,000 --> x<130,000

Now the new median is 330,000. As the only 2 values changing are that of Cal's and Ann's, this new median must be either the increased sales figure of Cal, or the deflated sales figure of Ann.

Cal : 330,000-190,000 =x = 140,000--> Not possible as x<130,000. Thus the median is the new sales figure of Ann --> 450,000-330,000 = 120,000.
D.
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Re: The table above shows the total sales recorded in July for the 5 sales [#permalink]

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06 Dec 2008, 05:21
Only Cal & Ann have the incorrect figures so $330k must be either belong to Ann or Cal If belong to Cal, as Ann's total sales, 680k, 360k > 330k, so the median is either Ann's or 360k Therefore 330k must be belong to Ann, Ann 330,000 Cal 310,00 Manager Joined: 06 Apr 2010 Posts: 144 Followers: 3 Kudos [?]: 737 [0], given: 15 Cal Sale [#permalink] ### Show Tags 29 Apr 2011, 01:56 Attachment: Cal Sale.JPG [ 20.37 KiB | Viewed 2000 times ] Senior Manager Joined: 03 Mar 2010 Posts: 440 Schools: Simon '16 (M) Followers: 5 Kudos [?]: 304 [0], given: 22 Re: Cal Sale [#permalink] ### Show Tags 29 Apr 2011, 03:24 CAL 190,000+X DOT 210,000 ANN 450000-X BOB 360,000 ED 680,000 Median is middle value if the number of terms are odd. Hence, 450000-x = 330,000 x=120,000 OA. D _________________ My dad once said to me: Son, nothing succeeds like success. Manager Joined: 15 Apr 2011 Posts: 65 Location: Bangalore India Schools: LBS, HBS, ISB, Kelloggs, INSEAD Followers: 2 Kudos [?]: 7 [0], given: 2 Re: Cal Sale [#permalink] ### Show Tags 29 Apr 2011, 04:46 jamifahad wrote: CAL 190,000+X DOT 210,000 ANN 450000-X BOB 360,000 ED 680,000 Median is middle value if the number of terms are odd. Hence, 450000-x = 330,000 x=120,000 OA. D How do you calculated that 450000 - x is the median here? _________________ Thanks, AM Manager Joined: 15 Apr 2011 Posts: 65 Location: Bangalore India Schools: LBS, HBS, ISB, Kelloggs, INSEAD Followers: 2 Kudos [?]: 7 [0], given: 2 Re: Cal Sale [#permalink] ### Show Tags 29 Apr 2011, 09:49 ramprakash wrote: A 4,50,000 B 3,60,000 C 1,90,000 D 2,10,000 E 6,80,000 Problem lies with sales of A & C...i.e. A' sales value 4,50,000 will have to be reduced by x and C's sales value will have to be increased by x. ( given in the problem ) After the correction/rearrangement the median value is 33,000 Keeping the other 3 sales values of B,D,E intact ?,2,10,000,3,30,000 (median),3,60,000,6,80,000 Two possibilities are there : 1.C's sales value of 1,90,000 would have been increased to 3,30,000..In that case, A's sales value becomes 3,10,000. This goes against the given information that A's sales is still higher than C. 2.So, we can conclude that A's sales value has been decreased to 3,30,000. Hence the incorrect value = 4,50,000 - 3,30,000 = 1,20,000 Hope I've made sense..Probably I've made it lengthy...!!! Thanks...thats explains it very clearly....actually I was not able to clearly identify this scenario. _________________ Thanks, AM VP Status: There is always something new !! Affiliations: PMI,QAI Global,eXampleCG Joined: 08 May 2009 Posts: 1335 Followers: 17 Kudos [?]: 254 [0], given: 10 Re: Cal Sale [#permalink] ### Show Tags 18 May 2011, 03:26 45-x > 19+x 19+x , 21, 36,45-x,68 median = 33 hence 45-x = 33 meaning x = 12. _________________ Visit -- http://www.sustainable-sphere.com/ Promote Green Business,Sustainable Living and Green Earth !! Director Joined: 28 Jul 2011 Posts: 550 Location: United States Concentration: International Business, General Management GPA: 3.86 WE: Accounting (Commercial Banking) Followers: 3 Kudos [?]: 238 [0], given: 16 The table above shows the total sales recorded in July for [#permalink] ### Show Tags 01 Feb 2012, 08:01 2 This post was BOOKMARKED Ann$450,000
Bob $360,000 Cal$190,000
Dot $210,000 Ed$680,000

The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A.$30,000
B. $48,000 C.$90,000
D. $120,000 E.$140,000
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Re: The table above shows the total sales recorded in July for [#permalink]

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01 Feb 2012, 16:20
Bunuel wrote:
Ann $450,000 Bob$360,000
Cal $190,000 Dot$210,000
Ed $680,000 The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was$330,000. What was the value of the incorrectly recorded sale?

A. $30,000 B.$48,000
C. $90,000 D.$120,000
E. $140,000 Old sales: {Cal=190, 210, 360, Ann=450, 680}. Now, the median of a set with odd # of terms is just a middle term (when ordered in ascending /descending order). So, old median=360. We know that new median=330 and Cal's sales are still less than Ann's, hence Ann's new sales must be 330 (Ann's sales # must be reduced so that it becomes the middle term: 360 and Ann must switch places): {210, Cal, Ann=330, 360, 680}. The value of the incorrectly recorded sale is Ann's old sales - Ann's new sales = 450 - 330 = 120. Answer: D. Hope it's clear. Hi Bunnel Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way {210, Cal, Ann=330, 360, 680}. Plz correct me if i am wrong _________________ +1 Kudos If found helpful.. Math Expert Joined: 02 Sep 2009 Posts: 38798 Followers: 7714 Kudos [?]: 105780 [0], given: 11581 Re: The table above shows the total sales recorded in July for [#permalink] ### Show Tags 01 Feb 2012, 16:25 kotela wrote: Hi Bunnel Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way {210, Cal, Ann=330, 360, 680}. Plz correct me if i am wrong First of all either Cal's or Ann's sales must be 330. Now, if Cal's sales are 330 then as Ann>Cal then the ordering would be {210, Cal=330, Ann>Cal, 360, 680} --> median={Ann's sales}>330, but we know that the median is 330, so this case is not possible. Hope it's clear. _________________ Director Joined: 28 Jul 2011 Posts: 550 Location: United States Concentration: International Business, General Management GPA: 3.86 WE: Accounting (Commercial Banking) Followers: 3 Kudos [?]: 238 [0], given: 16 Re: The table above shows the total sales recorded in July for [#permalink] ### Show Tags 01 Feb 2012, 18:22 Bunuel wrote: kotela wrote: Hi Bunnel Here how do we now that Ann's sales=330. The question says ann's sales were higher than cal's and we are not sure about any particular value and we too don't know how much cal's sales were increased, so how can we order the list in the this way {210, Cal, Ann=330, 360, 680}. Plz correct me if i am wrong First of all either Cal's or Ann's sales must be 330. Now, if Cal's sales are 330 then as Ann>Cal then the ordering would be {210, Cal=330, Ann>Cal, 360, 680} --> median={Ann's sales}>330, but we know that the median is 330, so this case is not possible. Hope it's clear. ya that makes sense... I always miss reading small parts in a sentence... _________________ +1 Kudos If found helpful.. Manager Status: Working hard to score better on GMAT Joined: 02 Oct 2012 Posts: 90 Location: Nepal Concentration: Finance, Entrepreneurship GPA: 3.83 WE: Accounting (Consulting) Followers: 0 Kudos [?]: 166 [0], given: 23 Re: The table above shows the total sales recorded in July for [#permalink] ### Show Tags 26 May 2013, 00:53 mydreammba wrote: Ann$450,000
Bob $360,000 Cal$190,000
Dot $210,000 Ed$680,000

The table above shows the total sales recorded in July for the 5 salespeople at Acme Truck Sales. It was discovered that one of Cal's sales was incorrectly recorded as one of Ann's sales. After this error was corrected, Ann's total sales were still higher than Cal's total sales, and the median of the 5 sales totals was $330,000. What was the value of the incorrectly recorded sale? A.$30,000
B. $48,000 C.$90,000
D. $120,000 E.$140,000

My approach:
As question stem tells that median is 330000, take a quick look for the other salesmen to match this median. None has 330000 sales. Thus this must of of either Ann's or cal's.

besides that question further tells ann's and cal's amount is misplaced. so let us try to make Ann's sells 330000. Then we have to reduce 12000. this will be added to cal's and become 310000. this satisfies the condition that:

Ann's sales amount > Cal's sales amount.

To verify check by making Cal's amount 330000 above mentioned condition will be violated.

Thus The misplaced amount is 120000.
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Re: The table above shows the total sales recorded in July for [#permalink]

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24 Jul 2014, 05:36
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Re: The table above shows the total sales recorded in July for the 5 sales [#permalink]

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06 Mar 2015, 15:55
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Re: The table above shows the total sales recorded in July for the 5 sales [#permalink]

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06 Mar 2015, 18:51
HI All,

Karishma's explanation is spot-on, so I won't rehash any of that here. I do want to point out that if the original poster had included the 5 answer choices, then we could have used them against the prompt and TESTed THE ANSWERS. That approach likely would have been easier (and taken less time) than the approach that we are all forced to take without having the answer choices. Remember that most questions on the Official GMAT can be approached in more than one way. Having the flexibility to solve problems in multiple ways can help you to score at a higher level on Test Day.

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Re: The table above shows the total sales recorded in July for [#permalink]

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14 May 2016, 08:35
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Re: The table above shows the total sales recorded in July for   [#permalink] 14 May 2016, 08:35
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