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Re: The Ultimate Q51 Guide [Expert Level]
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07 Jan 2020, 17:21
[GMAT math practice question] (Geometry) The figure shows right triangle ABC and AB = 5, BC = 4 and CA = 3. What is the area of triangle BDE? 1) AC = AD 2) AB is perpendicular to DE. Attachment:
1.3ds.png [ 22.3 KiB  Viewed 416 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since we have 2 variables (AD and EC) in the original condition, C is most likely the answer. We can figure out where D and E are by AD and EC. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) Attachment:
1.3ds(a).png [ 12.99 KiB  Viewed 416 times ]
Since triangles AED and AEC are congruent, we have DE = CE and DB = 5  3 = 2. The area of triangle ABC = (1/2)*4*3 = 6, which is also the sum of the areas of triangle ABE and triangle AEC. Then we have (1/2)*5*DE + (1/2)*3*CE = (5/2)DE + (3/2)DE = (8/2)DE = 4DE = 6. Thus, we have DE = 6/4, or DE = 3/2. The area of triangle DBE is (1/2)*DB*DE = (1/2)*2*(3/2) = 3/2. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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Re: The Ultimate Q51 Guide [Expert Level]
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08 Jan 2020, 23:44
[GMAT math practice question] (Geometry) The figure shows right triangle ABC and AB = 5, BC = 4 and CA = 3. What is the area of triangle BDE? 1) AC = AD. 2) AB is perpendicular to DE. Attachment:
1.3ds.png [ 22.3 KiB  Viewed 386 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since we have 2 variables (AD and EC) in the original condition, C is most likely the answer. We can figure out where D and E are by AD and EC. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) Attachment:
1.3ds(a).png [ 12.99 KiB  Viewed 386 times ]
Since triangles AED and AEC are congruent, we have DE = CE and DB = 5  3 = 2. The area of triangle ABC = (1/2)*4*3 = 6, which is also the sum of the areas of triangle ABE and triangle AEC. Then we have (1/2)*5*DE + (1/2)*3*CE = (5/2)DE + (3/2)DE = (8/2)DE = 4DE = 6. Thus, we have DE = 6/4, or DE = 3/2. The area of triangle DBE is (1/2)*DB*DE = (1/2)*2*(3/2) = 3/2. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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Re: The Ultimate Q51 Guide [Expert Level]
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09 Jan 2020, 19:33
[GMAT math practice question] (Inequalities) a, b and c are positive and a < 5. a, b and c satisfy a2  a  2b  2c = 0, and a + 2b  2c + 3 = 0. What is the order among a, b and c? A. c > a > b B. a > c > b C. a > b > c D. c > b > a E. b > c > a => When we add the two equations a^2  a  2b  2c = 0 and a + 2b  2c + 3 = 0, we have a^2  a  2b  2c + a + 2b  2c + 3 = 0 + 0, a^2 – 4c + 3 = 0 or 4c = a^2 + 3. When we subtract 4a from the both sides of the last equation, we have 4c  4a = a^2  4a + 3, 4(c  a) = (a  1)(a  3). Rearranging the equations given in the question gives us a^2  a = 2(b + c) and a + 3 = 2(c  b) given in the question. When we subtract a + 3 = 2(c  b) from a^2  a = 2(b + c), we have a^2  a  (a + 3) = 2(b + c)  2(c  b), a^2  a  a  3 = 2b + 2c  2c +2b, 4b = a^2 – 2a – 3, 4b = (a  3)(a + 1) > 0 and a > 3. We have 4(c  a) = (a  1)(a  3) > 0 or c > a since a > 3 and (a  1)(a  3) > 0. We have 4(b  a) = 4b – 4a and 4b – 4a = a^2 – 2a – 3 – 4a (because 4b = a^2 – 2a – 3). Then 4b  4a = a^2 – 6a – 3 = a(a  3) – 3(a  3) – 12 = (a  3)2  12 < 0 or b < a since 3 < a < 5. Thus, we have c > a > b. Therefore, A is the answer. Answer: A
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Re: The Ultimate Q51 Guide [Expert Level]
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12 Jan 2020, 17:51
[GMAT math practice question] (Geometry) As the figure below shows, △ABC is a right triangle. What is the measure of ∠B? 1) DM is a perpendicular bisector of segment AB. 2) ∠MAD = ∠CAD Attachment:
1.6ds.png [ 14.59 KiB  Viewed 361 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary. Condition 1) tells us that triangle ABD is isosceles with BD = AC and ∠B = ∠MBD = ∠MAD. Condition 2) tells us that ∠MAD = ∠CAD. Since ∠C = 90, we have ∠MBD + ∠MAD + ∠CAD + ∠C = 180, ∠MBD + ∠MAD + ∠CAD + 90 = 180, or ∠MBD + ∠MAD + ∠CAD = 90 and ∠MBD = ∠MAD = ∠CAD. As each angle is the same and all three add up to 90, each angle must be 30. Thus we have ∠B = ∠MBD = 30. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C
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Re: The Ultimate Q51 Guide [Expert Level]
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13 Jan 2020, 17:40
[GMAT math practice question] (Inequalities) x is an integer. y and z are real numbers with x < 2y < 3z. What is the value of x? 1) x + 2y + 3z = 4 2) 2x + 3y + 4z = 5 => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary. Since we have 3 variables (x, y, and z) and 0 equations, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) We have x + 2y + 3z = 4 and 2x + 3y + 4z = 5. When we subtract twice the second equation from three times the first equation, we have 3(x + 2y + 3z)  2(2x + 3y + 4z) = 3(4)  2(5) 3x + 6y + 9z  4x  6y  8z = 12  10 x + z = 2 z = x + 2. Substituting z = x + 2 into the first equation gives us: x + 2y + 3z = 4 x + 2y + 3(x + 2) = 4 x + 2y + 3x + 6 = 4 4x + 2y = 2 2y = 4x  2 y = 2x – 1 x < 2y < 3z is equivalent to x < 2(2x – 1) < 3(x + 2), or x < 4x – 2 < 3x + 6. Then we have x < 2/5 from x < 4x – 2, because: x < 4x – 2 5x < 2 x < 2/5. We also have x > 8/7 from 4x  2 < 3x + 6, because: 4x  2 < 3x + 6 7x < 8 x > 8/7 (the inequality sign changes direction since we divided by a negative) Thus 8/7 < x < 2/5 and x = 1 since x is an integer. Since both conditions together yield a unique solution, they are sufficient. Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B. Condition 1) x = 2, y = 1, z = 4/3 and x = 3, y = 0, z = 1 are solutions. Condition 2) x = 2, y = 0, z = 9/4 and x = 1, y = 0, z = 7/4 are solutions. Since condition 2) does not yield a unique solution, it is not sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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Re: The Ultimate Q51 Guide [Expert Level]
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14 Jan 2020, 20:10
[GMAT math practice question] (Function) A function f(x) is defined as x *<x>. If <x> is the greatest factor of x except x, what is f(500)? A. 1000 B. 5000 C. 15000 D. 120000 E. 125000 => All the factors of 500 are 1, 2, 4, 5, 10, 20, 25, 50, 100, 125, 250 and 500. Thus <500> = 250. Then f(500) = 500*250 = 125000. Therefore, E is the answer. Answer: E
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Re: The Ultimate Q51 Guide [Expert Level]
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15 Jan 2020, 17:24
[GMAT math practice question] (Coordinate Geometry) The line y = ax  1 passes through (1/3, 0). On the line, there is a point whose xcoordinate and ycoordinate are the same. What is this point? A. (1/5 , 1/5) B. (1/3 , 1/3) C. (1/2 , 1/2) D. ( 1/4 ,  1/4) E. ( 1/5 ,  1/5) => Since the line y = ax – 1 passes through (1/3, 0), we have 0 = a/3 – 1 or a = 3. To figure out the point with the same xcoordinate and ycoordinate on the line y = 3x – 1, we make y = x, which gives us x = 3x – 1 or 2x = 1. Thus we have x = 1/2, y = 1/2, and the point is (1/2, 1/2). Therefore, C is the answer. Answer: C
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The Ultimate Q51 Guide [Expert Level]
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16 Jan 2020, 17:25
[GMAT math practice question] (Coordinate Geometry) The following figure shows line l: y = 2x. If the area of BOC is 8, what is the area of triangle AOB? A. 4 B. 6 C. 8 D. 11 E. 13 Attachment:
1.8ps.png [ 7.31 KiB  Viewed 280 times ]
=> Since the area of the triangle OBC is 8 and the length of the base OC is 4, and the area of a triangle = 1/2bh, we have: 8 = 1/2(4)h 8 = 2h h = 4. The height of the triangle is 4, and the ycoordinate of point B is 4. Since point B is on the line y = 2x, we have 4 = 2x or x = 2. Then we have point B(2, 4). We can then determine the equation of the line passing through B (2, 4) and C (4, 0). We first determine the slope of the line using the equation (y 1  y 2) / (x 1  x 2) (4  0) / (2  4) 4 / 2 Slope = m = 2. Then, using the point (4, 0) and m = 4 we get: y = mx + b 0 = 2(4) + b b = 8 The line passing through B and C is y = 2x + 8. Point A has an xcoordinate of 0, so y = 2(0) + 9, or y = 8. Then we have point A(0,8). The triangle AOB has base OA = 8, and the height equals 2 since the xcoordinate of B is 2. Then the area of triangle OAB is (1/2)*8*2 = 8. Therefore, C is the answer.
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The Ultimate Q51 Guide [Expert Level]
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19 Jan 2020, 17:52
[GMAT math practice question] (Number Properties) x, y, and z are integers with 3 ≤ x < y < z ≤ 30 and y is a prime number. What is the value of x + y + z? 1) 1/x + 1/y = 1/2 + 1/z 2) 2xy = z => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary. Condition 2) x = 3, y = 5, z = 2*3*5 = 30 are unique solutions as it is the only combination of numbers that works within the given conditions of 3 ≤ x < y < z ≤ 30 and y is a prime number. If x and y are larger numbers than z is greater than 30. We then have x + y + z = 3 + 5 + 30 = 38. Since condition 2) yields a unique solution, it is sufficient. Condition 1) Since 3 ≤ x < y < z ≤ 30, we have 1/30 ≤ 1/z < 1/y < 1/x ≤ 1/3 when we take reciprocals. Since we have 1/x + 1/y = 1/2 + 1/z, we have 1/2 < 1/x + 1/y < 1/x + 1/x = 2/x or 1/2 = 2/4 < 1/x. Thus x < 4 and we have x = 3. Since we have 1/2 = 1/3 + 1/y, we have 1/6 < 1/y or y < 6. Since 3 < y < 6 and y is a prime number, we have y = 5. 1/z = 1/x + 1/y – 1/2 = 1/3 + 1/5 – 1/2 = 10/30 + 6/30 – 15/30 = 1/30 or z = 30. Then, x + y + z = 3 + 5 + 30 = 38. Since condition 1) yields a unique solution, it is sufficient. Therefore, D is the answer. Answer: D This question is a CMT 4(B) question: condition 2) is easy to work with, and condition 1) is difficult to work with. For CMT 4(B) questions, D is most likely the answer.
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Re: The Ultimate Q51 Guide [Expert Level]
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20 Jan 2020, 17:36
[GMAT math practice question] (Algebra) What is k? 1) 3x + 5y = k + 1 and 2x + 3y = k 2) x + y = 2 => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary. Since we have 3 variables (x, y, and k) and 0 equations, E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) Since x + y = 2, we have y = 2 – x. Substituting y = 2  x into 3x + 5y = k + 1 gives us 3x + 5(2  x) = k + 1, 3x + 10  5x = k + 1, 2x + 10 = k + 1 or 2x + k = 9. Substituting y = 2  x into 2x + 3y = k gives us 2x + 3(2  x) = k, 2x + 6 = 3x = k, x + 6 = k or x + k = 6. We now have 2 equations: 2x + k = 9 and x + k = 6. Rewriting the first equation gives us k = 9  2x. Substituting this into the second equation gives us x + 9  2x = 6, x = 3, and x = 3. Then x + k = 6 becomes 3 + k = 6, and k = 3. Then we have x = 3 and k = 3. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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Re: The Ultimate Q51 Guide [Expert Level]
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21 Jan 2020, 17:43
[GMAT math practice question] (Coordinate Geometry) The figure shows that OABC is a parallelogram. What is the equation of the line passing through A and C? A. y = 1/10x + 3/10 B. y = 5/11x + 20/11 C. y = 5/12x + 3/12 D. y = 1/13x + 3/13 E. y = 5/14x + 3/14 Attachment:
1.13PS.png [ 12.51 KiB  Viewed 209 times ]
=> Since AB = CO = 4, we have point C(4, 0). Then the slope of the line AC is (5  0) / (7  (4)) = 5/11. The equation of the line AC is y  0 = (5/11)(x  (4)) or y = (5/11)x + 20/11. Therefore, B is the answer. Answer: B
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Re: The Ultimate Q51 Guide [Expert Level]
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27 Jan 2020, 06:05
[GMAT math practice question] (Probability) On each face of a cube, one of 1, 2 or 3 is written. The number of 1’s on a face is a, the number of 2’s is b, and the number of 3’s is c. What is c? 1) a = 2 and b = 3. 2) The probability of throwing the two identical cubes and getting a sum of 3 is 1/3. => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question. We should simplify conditions if necessary. We have 3 variables and 1 equation. However, we should check condition 1) alone first, since it has 2 equations. Condition 1) Since we have a + b + c = 6, a = 2 and b = 3, we have 2 + 3 + c = 6, 5 + c = 6, and c = 1. Since condition 1) yields a unique solution, it is sufficient. Condition 2) Condition 2) tells us that c/6 + c/6 = 1/3, (2c)/6 = 1/3, c/3 = 1/3, c = 3/3. Then we have c = 1. Since condition 2) yields a unique solution, it is sufficient. Therefore, D is the answer. Answer: D
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Re: The Ultimate Q51 Guide [Expert Level]
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27 Jan 2020, 18:23
[GMAT math practice question] (Probability) What is the probability that a threedigit integer corresponding with the three numbers thrown on three different dice is a multiple of 11? A. 1/3 B. 2/27 C. 4/27 D. 5/27 E. 2/9 => In order for a threedigit integer abc to be a multiple of 11, a – b + c must be a multiple of 11 since we have 100a + 10b + c = 99a + a + 11b – b + c = (99a + 11b) + a – b + c = 11(9a+b) + a – b +c. If a – b + c = 0, then the possible cases for (a, b, c) are (1, 2, 1), (1, 3, 2), (1, 4, 3), (1, 5, 4), (1, 6, 5), (2, 3, 1), (2, 4, 2), (2, 5, 3), (2, 6, 4), (3, 4, 1), (3, 5, 2), (3, 6, 3), (4, 5, 1), (4, 6, 2) and (5, 6, 1), and we have 15 cases. If a – b + c = 11, then we have only the case (a, b, c) = (6, 1, 6). Thus the probability is 16/(6^3) = 16/216 = 2/27. Therefore, the answer is B. Answer: B
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Re: The Ultimate Q51 Guide [Expert Level]
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28 Jan 2020, 17:47
[GMAT math practice question] (Geometry) Is triangle ADE an isosceles triangle? 1) AB = AC 2) BD = CE Attachment:
1.21DS.png [ 7.09 KiB  Viewed 164 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since triangle ADE has three sides, we have 3 variables and 0 equations, and E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) When we consider condition 1), triangle ABC is an isosceles triangle, and ∠B and ∠C are congruent. Since BD = EC from condition 2) and we have AB = AC, and ∠B = ∠C, triangles ABD and ACE are congruent to each other using the SAS property. Thus, we have AD = AE, and the triangle ADE is isosceles. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions on which the answer is A, B, C, or D.
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Re: The Ultimate Q51 Guide [Expert Level]
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29 Jan 2020, 17:27
[GMAT math practice question] (Geometry) The figure shows that ∠ABC is 80. What is ∠ADC? 1) Point O is the circumcenter of △ABC. 2) Point O is the circumcenter of △ACD. Attachment:
1.24DS.png [ 9.51 KiB  Viewed 148 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since we have 4 angles of a quadrilateral, we have 4 variables (∠A, ∠B, ∠C, and ∠D) and 2 equations (∠B = 80 and ∠A + ∠B + ∠C + ∠D = 360), and E is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) When we consider both conditions together, we have a quadrilateral inscribed by a circle and ∠B + ∠D = 180. Since we have ∠B = 80, we have ∠D = 100. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C Normally, in problems which require 2 equations, such as those in which the original conditions include 2 variables, or 3 variables and 1 equation, or 4 variables and 2 equations, each of conditions 1) and 2) provide an additional equation. In these problems, the two key possibilities are that C is the answer (with probability 70%), and E is the answer (with probability 25%). Thus, there is only a 5% chance that A, B, or D is the answer. This occurs in Common Mistake Types 3 and 4. Since C (both conditions together are sufficient) is the most likely answer, we save time by first checking whether conditions 1) and 2) are sufficient, when taken together. Obviously, there may be cases in which the answer is A, B, D, or E, but if conditions 1) and 2) are NOT sufficient when taken together, the answer must be E.
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30 Jan 2020, 17:19
[GMAT math practice question] (Probability) There are six cards numbered 0, 0, 1, 2, 3, and 4. How many 3digit even numbers are possible when picking 3 cards? A. 30 B. 32 C. 34 D. 36 E. 38 => Case 1: X00 (We have two zero digits.) The number of possible cases is 4. Case 2: X0Y / XY0 (We have one zero digit.) X0Y: The number of possible values of y is 2 since y is an even number. Then the number of possible values of x is 3. Thus we have 2 * 3 = 6 cases. XY0: The number of possible cases is 4 * 3 = 12 When we have one zero digit, we have 6 + 12 = 18 cases. Case 3: XYZ (We don’t have any zero digits.) The number of possible values of z is 2 since z is an even number. Then we have 3 * 2 = 6 cases for each even integer z. Thus we have 6 * 2 = 12 cases. Then we have 4 + 18 + 12 = 34 cases. Therefore, the answer is C. Answer: C
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02 Feb 2020, 18:32
[GMAT math practice question] (Geometry) What is the measure of ∠BOC in the figure? 1) Point O is the circumcenter of triangle ABC. 2) ∠OAC = 23° and ∠OBA = 48° Attachment:
1.27DS.png [ 13.67 KiB  Viewed 110 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since we have 4 variables (∠BOC, ∠ABC, ∠BCA, and ∠CAB) and 1 equation (∠ABC + ∠BCA + ∠CAB = 180°), C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) Since point O is the circumcenter of triangle ABC from condition 1), triangles OAB, OBC, and OCA are isosceles and OA, OB, OC are congruent. Since ∠OAC = 23°, we have ∠OCA = 23° (because it is an isosceles triangle) and ∠AOC = 134° (180°  23°  23°). Since ∠OBA = 48°, we have ∠OAB = 48° and ∠AOB = 84°. Then we have ∠AOB + ∠BOC + ∠COA = 360°, 134° + 84° + ∠BOC = 360°, 218° + ∠BOC = 360° or ∠BOC = 142°. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B, or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions in which the answer is A, B, C, or D.
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03 Feb 2020, 18:14
[GMAT math practice question] (Geometry) The figure shows that ∠BAD is 30°, and ∠CAE is 40°. What is the measure of ∠ADE? 1) Point O is the circumcenter of triangle ABC. 2) Point I is the incenter of triangle ABC. Attachment:
1.30DS.png [ 7.84 KiB  Viewed 91 times ]
=> Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Visit https://www.mathrevolution.com/gmat/lesson for details. Since we have 6 variables (∠ABC, ∠BCA, ∠CAB, ∠ADE, ∠DAE, and ∠DEA) and 2 equations (∠ABC + ∠BCA + ∠CAB = 180°, ∠ADE + ∠DAE + ∠DEA = 180°), C is most likely the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first. Conditions 1) & 2) Since point I is the incenter of triangle ABC, we have ∠IAB = ∠IAC = 40° and ∠DAE = ∠IAB  ∠BAD, ∠DAE = 40°  30°, ∠DAE = 10° . Since point O is the circumcenter of triangle ABC, we have ∠BAO = ∠ABO = 30° and ∠OBC = ∠OCB = (1/2)(180° – (2*30° + 2*50°)) = 10°. Then ∠ABC = ∠ABO + ∠OBC = 30° + 10° = 40°. Since ∠ADE is an exterior angle of triangle ABD, we have ∠ADE = ∠DAB + ∠ABD = 30° + 40° = 70°. Since both conditions together yield a unique solution, they are sufficient. Therefore, C is the answer. Answer: C In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B, or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2) when taken together. Obviously, there may be occasions in which the answer is A, B, C, or D.
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04 Feb 2020, 17:18
[GMAT math practice question] (Geometry) Point I is the incenter of triangle ABC in the figure. The figure shows AB = 10, AC = 8, ∠ABI = 22° and ∠ACI = 30°. Line DE is parallel to line BC. What is the length of the perimeter of triangle ADE? Attachment:
1.27DS.png [ 13.67 KiB  Viewed 78 times ]
A. 14 B. 16 C. 18 D. 20 E. 22 => Since I is the incenter of the triangle ABC, IB and IC bisect ∠ABC and ∠ACB, respectively. We know ∠IBC = 22° and ∠ICB = 30°. Since ∠DIB and ∠CBI are alternate interior angles, we have ∠BID = 22° and triangle DBI is an isosceles. Since ∠EIC and ∠BCI are alternate interior angles, we have ∠EIC = 30° and triangle CEI is an isosceles. Thus we have the perimeter of triangle ADE = AD + DE + EA = AD + DI + IE + EA = AD + DB + CE + EA = AB + AC = 10 + 8 = 18. Therefore, C is the answer. Answer: C
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The Ultimate Q51 Guide [Expert Level]
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05 Feb 2020, 17:20
[GMAT math practice question] (Geometry) Point O is the circumcenter of triangle ABC, and the length of AC is 7. The length of the perimeter of triangle ABC is 19. What is the area of the circumscribed circle of triangle ABC? A. 30π B. 32π C. 34π D. 36π E. 38π Attachment:
1.28ps.png [ 8.69 KiB  Viewed 49 times ]
=> Since point O is the circumcenter of triangle ABC, OA = OB = OC is the radius of the circumscribed circle of the triangle. Since the perimeter of the triangle ABC is 19, we have OA + OC + 7 = 19, OA + OA + 7 = 19, 2(OA) + 7 = 19, 2(OA) = 12, or the radius OA = 6. Thus, the area of the circumscribed circle of the triangle is (62)π = 36π. Therefore, the answer is D. Answer: D
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The Ultimate Q51 Guide [Expert Level]
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