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The value of a diamond varies directly as the square of its weight. If

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Joined: 29 Nov 2018
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Concentration: Marketing, Strategy
The value of a diamond varies directly as the square of its weight. If  [#permalink]

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03 Feb 2019, 09:42
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74% (01:38) correct 26% (01:13) wrong based on 24 sessions

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The value of a diamond varies directly as the square of its weight. If a diamond falls and breaks into two pieces with weights in the ratio 2 : 3, what is the loss percentage in the value?
A 10%
B. 16.66%
C. 25%
D 40%
E 48%
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Re: The value of a diamond varies directly as the square of its weight. If  [#permalink]

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03 Feb 2019, 10:29
cfc198 wrote:
The value of a diamond varies directly as the square of its weight. If a diamond falls and breaks into two pieces with weights in the ratio 2 : 3, what is the loss percentage in the value?
A 10%
B. 16.66%
C. 25%
D 40%
E 48%

$$V = kW^2$$

Let the original piece be 5 unit...

SO, Value of the diamond is $$V = 25k$$

When the piece breaks its value becomes $$V_2 = 4k$$ & $$V_3 = 9K$$, Total value of the broken piece is $$13k$$

Hence the percentage loss in weight is $$\frac{25k-13k}{25k}*100$$ = 48%, Answer must be (E)
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Re: The value of a diamond varies directly as the square of its weight. If   [#permalink] 03 Feb 2019, 10:29
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