GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 18 Jul 2018, 03:57

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

The violent crime rate (number of violent crimes per 1,000 residents)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Expert Post
Top Contributor
CEO
CEO
User avatar
P
Joined: 12 Sep 2015
Posts: 2633
Location: Canada
Re: The violent crime rate (number of violent crimes per 1,000 residents) [#permalink]

Show Tags

New post 13 Mar 2018, 14:22
Top Contributor
janet1511 wrote:
The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

(A) changes in the population density of both Parkdale and Meadowbrook over the past four years

(B) how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

(C) the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

(D) the violent crime rates in Meadowbrook and Parkdale four years ago

(E) how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures


The information in the passage AND the conclusion should sound somewhat "fishy"
All we're told is that Meadowbrook's and Parkdale's crime rate have increased 60% and 10% respectively in the past 4 years. HOWEVER, we know nothing about the crime rate statistics from 4 years ago.

Consider this possible scenario.
4 years ago: Meadowbrook's crime rate was 10 violent crimes per 1,000 residents
4 years ago: Parkdale's crime rate was 900 violent crimes per 1,000 residents

So, given the increases in crime, we can conclude that:
Present: Meadowbrook's crime rate is 16 violent crimes per 1,000 residents (going from 10 to 16 represents a 60% increase)
Present: Parkdale's crime rate was 990 violent crimes per 1,000 residents (going from 900 to 990 represents a 10% increase)

Can we conclude that Meadowbrook's residents are more likely to become victims of violent crime than are residents of Parkdale?
Absolutely not!

So, we should be looking for an answer choice that explains why we need to know the crime rates from 4 years ago.

Only answer choice D does this.

Answer: D

Cheers,
Brent
_________________

Brent Hanneson – Founder of gmatprepnow.com

Image

VP
VP
User avatar
P
Status: Learning
Joined: 20 Dec 2015
Posts: 1203
Location: India
Concentration: Operations, Marketing
GMAT 1: 670 Q48 V36
GRE 1: Q157 V157
GPA: 3.4
WE: Manufacturing and Production (Manufacturing)
Reviews Badge CAT Tests
Re: The violent crime rate (number of violent crimes per 1,000 residents) [#permalink]

Show Tags

New post 20 Mar 2018, 23:11
janet1511 wrote:
The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

The argument above is flawed because it fails to take into account

(A) changes in the population density of both Parkdale and Meadowbrook over the past four years

(B) how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale

(C) the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale

(D) the violent crime rates in Meadowbrook and Parkdale four years ago

(E) how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures


This is a trap question regarding percentages and it forces us to believe to take absolute numbers for percentages.
Also we given violent crime per 1000 .
Imo D

If we know the crime rates in the two cities before four years we can reach some conclusion.If they were more in one country and less in some country they only we can reach conclusion.
A This is not required and it is irrelevant as we already have rates that have increased.
B Again this not required as we are already given rates.
C Not required as we just concerned with violent crimes .
D correct
E Out of scope .
_________________

Please give kudos if you found my answers useful

Intern
Intern
avatar
B
Joined: 04 Aug 2017
Posts: 14
Premium Member CAT Tests
Re: The violent crime rate (number of violent crimes per 1,000 residents) [#permalink]

Show Tags

New post 22 Mar 2018, 08:28
The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of Parkdale.

what if 4 years ago
Maedowbrook crime rate was 100 -> after 60% increase its 160. diff- 60
Parkdale crime rate was 1000-> after 10% increase its 1100 diff -100

Hence knowing the crime rate prior to 4 years is crucial. ANs is D
Re: The violent crime rate (number of violent crimes per 1,000 residents)   [#permalink] 22 Mar 2018, 08:28

Go to page   Previous    1   2   3   [ 44 posts ] 

Display posts from previous: Sort by

The violent crime rate (number of violent crimes per 1,000 residents)

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  

Events & Promotions

PREV
NEXT


cron

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.