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# The violent crime rate (number of violent crimes per 1,000

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Intern
Joined: 02 Jan 2009
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The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:04
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Question Stats:

56% (01:40) correct 44% (00:46) wrong based on 1237 sessions

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The violent crime rate (number of violent crimes per 1,000 residents) in Meadowbrook is 60 percent higher now than it was four years ago. The corresponding increase for Parkdale is only 10 percent. These figures support the conclusion that residents of Meadowbrook are more likely to become victims of violent crime than are residents of
Parkdale.

The argument above is flawed because it fails to take into account
A. changes in the population density of both Parkdale and Meadowbrook over the past four years
B. how the rate of population growth in Meadowbrook over the past four years compares to the corresponding rate for Parkdale
C. the ratio of violent to nonviolent crimes committed during the past four years in Meadowbrook and Parkdale
D. the violent crime rates in Meadowbrook and Parkdale four years ago
E. how Meadowbrook’s expenditures for crime prevention over the past four years compare to Parkdale’s expenditures
[Reveal] Spoiler: OA
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:17
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e.g
ratio of crimes M: P = 100: 200

M -->1000 --> 100 (four years ago) --> 160 (now : 60% more)
P -->1000 --> 200 (four years ago) --> 220 (now : 10% more)

Who is more likely to become victims : P..

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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:23
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Its B
let me explain

A. changes in the population density of both Parkdale and Meadowbrook over the
past four years ---density has no corelation here
B. how the rate of population growth in Meadowbrook over the past four years
compares to the corresponding rate for Parkdale
C. the ratio of violent to nonviolent crimes committed during the past four years in
Meadowbrook and Parkdale --ratio does not matter
D. the violent crime rates in Meadowbrook and Parkdale four years ago --OOS
E. how Meadowbrook’s expenditures for crime prevention over the past four years
compare to Parkdale’s expenditures--totally OOS
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:32
x2suresh

do you mean D? C is talking about the ratio of violent to nonviolent crimes

x2suresh wrote:
e.g
ratio of crimes M: P = 100: 200

M -->1000 --> 100 (four years ago) --> 160 (now : 60% more)
P -->1000 --> 200 (four years ago) --> 220 (now : 10% more)

Who is more likely to become victims : P..

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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:39
Agreed D
I meant that if there is high base % increase does not represent true picture
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 08:58
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janet1511 wrote:
x2suresh

do you mean D? C is talking about the ratio of violent to nonviolent crimes

x2suresh wrote:
e.g
ratio of crimes M: P = 100: 200

M -->1000 --> 100 (four years ago) --> 160 (now : 60% more)
P -->1000 --> 200 (four years ago) --> 220 (now : 10% more)

Who is more likely to become victims : P..

Sorry yeap.. I mean D.
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Mar 2009, 09:24
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D, since the argument only shows a relative increase and not an absolute increase, e.g. a 10% rise from 100 crimes per 1,000 residents (+10) is more than a 60% rise from 10 crimes per 1,000 residents (+6).
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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28 Feb 2010, 18:10
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Agree with D.

4 yrs ago M has violent rate 100. 4 yrs after it is increased by 60%...it becomes 160

4 yrs ago P has violent rate 200. 4 yrs after it is increased by 10%...it becomes 220

This shows that residents of P are more victims than M. Argument fails to consider this. Therefore, IMO d
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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01 Mar 2010, 09:25
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First my choice was B. But after reading the reasons for D, I too feel D is the correct option.

What is OA?
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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03 Mar 2010, 00:14
D it is as posted by reply2psg
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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12 Nov 2011, 21:52
D wins !
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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13 Nov 2011, 00:06
I agree with D. The number and statistic in this question quite easy, but the thing we need is to read the right answer express correctly our idea.
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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15 Nov 2011, 20:27
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D
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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20 Nov 2011, 22:42
D looks correct to me
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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17 Jan 2012, 10:30
Any time the argument talks about percentages, we need to look for an answer that talks about absolute numbers.

Hence, D!
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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25 Jan 2012, 09:52
Agree with D
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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25 Jan 2012, 23:46
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the best answer is D.But i feel even D is flawed.We need to know the absolute number of crimes in both the cities 4 years ago,the rates are not going to give a clear answer.
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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27 Jan 2012, 17:18
+1 D
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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13 Apr 2012, 21:46
the argument fails to look at what the starting point is. and only D addresses this.
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Re: The violent crime rate (number of violent crimes per 1,000 [#permalink]

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21 Apr 2012, 11:49
I can see why D was selected, but can someone explain why A is incorrect?

If the population density if each city is different, would that not have an effect on the figures that are given in the stimulus?
Re: The violent crime rate (number of violent crimes per 1,000   [#permalink] 21 Apr 2012, 11:49

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