Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 01:49

1

This post received KUDOS

23

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

72% (02:20) correct
28% (02:13) wrong based on 474 sessions

HideShow timer Statistics

The volume of water in a certain tank is x percent greater than it was one week ago. If r percent of the current volume of water in the tank is removed, the resulting volume will be 90 percent of the volume it was one week ago. What is the value of r in terms of x?

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 03:42

1

This post received KUDOS

1

This post was BOOKMARKED

Volume now is x% greater than volume one week ago => Vnow = Vweekago (1+x/100)

If r percent of the current volume is removed, the resulting volume will be 90 percent of the volume a week ago => Vnow (1-r/100) = 0.9*Vweekago

Using the first equation, Vnow/Vweekago = (1+x/100) Putting this in the second equation, (1-r/100) (1+x/100) = 0.9 => (100 - r) (100 + x) = 9000 => r = 100 - [9000/(100+x)] => r = 100* (10+x)/(100+x)

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 03:54

22

This post received KUDOS

8

This post was BOOKMARKED

Best approach for solving this specific problem would be "Pick numbers". You can also solve it in Algebraic way, but it could be time consuming and tedious.

Given that, the water was increased by x percent -> then reduced by r percent -> to 90 percent of what it was one week ago. Consider, the 100 units of water was increased by 20% to 120 units -> then reduced by 25% of 120 (i.e. by 30 units) -> to 90 units. i.e. Pick numbers as x = 20% and r = 25%

Substitute x=20 and identify the answer that gives r=25 A) x+10 --20+1=30 b) 10x+1 --200+1=201 c) 100(x+10) --100(20+10)=3000 d) 100( x+10/x+100) --100(20+10/20+100) = 100(30/120)=25 e) 100 ( 10x+1/10x+10) -- 100(200+1/200+10)= 100(201/210)

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 10:24

PraPon wrote:

Best approach for solving this specific problem would be "Pick numbers". You can also solve it in Algebraic way, but it could be time consuming and tedious.

Given that, the water was increased by x percent -> then reduced by r percent -> to 90 percent of what it was one week ago. Consider, the 100 units of water was increased by 20% to 120 units -> then reduced by 25% of 120 (i.e. by 30 units) -> to 90 units. i.e. Pick numbers as x = 20% and r = 25%

Substitute x=20 and identify the answer that gives r=25 A) x+10 --20+1=30 b) 10x+1 --200+1=201 c) 100(x+10) --100(20+10)=3000 d) 100( x+10/x+100) --100(20+10/20+100) = 100(30/120)=25 e) 100 ( 10x+1/10x+10) -- 100(200+1/200+10)= 100(201/210)

Hence choice(D) is the answer.

I think that in this scenario under pressure someone could not visualize 25% to obtain 90 and to go in the wrong way.

better an hybrid approach and in this case algebraic translation maybe is a bit safer
_________________

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 16:09

2

This post received KUDOS

2

This post was BOOKMARKED

Yes I agree, not all problems can be solved using pick numbers strategy or not always will be able to come up with ideal pick numbers under pressure. At times for complex problems, you need pen down that lengthy/heavy algebraic computations. However, giving 5 seconds to think about execution method (pick numbers, backsolving or algebraic) after reading the problem, can help saving over 40-50 seconds of 'extra' time taken by algebraic method.

In this specific problem, I tried to visualize how can I increase 100 to certain number and decrease to obtain 90?? First comes 110, but reducing it by 20 doesnt give integer percentage on 110. Next we have 120 that includes 20% increase and then 25% decrease gives 90..bingo! It took 5-7 seconds to think & 15-20 seconds to back-solve, but saved 40-50 seconds of algebraic calculations!

Picking number requires strategy of identifying optimum numbers using LCM, LCD, prime factors, multiples of 10/100s.

How do we get used to this method? Practice!!

When solving OG or practice problems, always see if you can solve it using multiple ways. Try same problem with Algebra, back-solving, pick numbers, hybrid approach (whichever methods are applicable) and even try guessing it. You may also automatically build that intuition over the time.
_________________

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jan 2013, 16:44

1

This post received KUDOS

Another consideration. be flexible

here we have something go up for a certain % and the go down for a certain % to have some result, here is 90. Ok 90 is our target value or our landmark

but what about if we think in a more abstract way ?? even if I increase my % of 20 or 30 and then decrease the same by any % to obtain a value of less than 100........the process is the same.

The gmat questions are so consistent and coherent (two word to say the same thing, indeed) that if you use several approachs they conduct you to the same answer, MUST conduct you to the same place. For this reason you can attack a problem with different stategies

Infact, even if you have 85 and not 90 as target value the answer is still D. Of course , this kind of resilience is acquired after you repeat over and over again the concepts behind
_________________

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

26 Jan 2013, 07:43

PraPon wrote:

Best approach for solving this specific problem would be "Pick numbers". You can also solve it in Algebraic way, but it could be time consuming and tedious.

Given that, the water was increased by x percent -> then reduced by r percent -> to 90 percent of what it was one week ago. Consider, the 100 units of water was increased by 20% to 120 units -> then reduced by 25% of 120 (i.e. by 30 units) -> to 90 units. i.e. Pick numbers as x = 20% and r = 25%

Substitute x=20 and identify the answer that gives r=25 A) x+10 --20+1=30 b) 10x+1 --200+1=201 c) 100(x+10) --100(20+10)=3000 d) 100( x+10/x+100) --100(20+10/20+100) = 100(30/120)=25 e) 100 ( 10x+1/10x+10) -- 100(200+1/200+10)= 100(201/210)

Hence choice(D) is the answer.

Thanks so much for this way. My owm method costs me 5 minutes to solve this question. The most difficult point is to estimate x and r as interger (First time I tried picking randomly and reached r=2/11% which made me unable to put into the formula). I try starting with 100 as the amount of water last week --> the amount of water this week after removing r percent is 90% of 100 = 90. I figure out r and x by finding a common multiple of 9 and 10 and larger than 100 (e.g. 180) --> figure out 180 for the first week (x=80%) and r=50%.

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

20 Jul 2013, 08:41

1

This post received KUDOS

Its actually the same if you cross multiply you arrive at the same equation. Since the question talks about percent increase its easier to write that way

For example if the question was 1000 is increased by X % and then by y % it would be \(1000( 1 + \frac{x}{100})(1+\frac{y}{100})\)
_________________

Click +1 Kudos if my post helped...

Amazing Free video explanation for all Quant questions from OG 13 and much more http://www.gmatquantum.com/og13th/

GMAT Prep software What if scenarios http://gmatclub.com/forum/gmat-prep-software-analysis-and-what-if-scenarios-146146.html

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

17 Oct 2013, 03:34

carcass wrote:

PraPon wrote:

Best approach for solving this specific problem would be "Pick numbers". You can also solve it in Algebraic way, but it could be time consuming and tedious.

Given that, the water was increased by x percent -> then reduced by r percent -> to 90 percent of what it was one week ago. Consider, the 100 units of water was increased by 20% to 120 units -> then reduced by 25% of 120 (i.e. by 30 units) -> to 90 units. i.e. Pick numbers as x = 20% and r = 25%

Substitute x=20 and identify the answer that gives r=25 A) x+10 --20+1=30 b) 10x+1 --200+1=201 c) 100(x+10) --100(20+10)=3000 d) 100( x+10/x+100) --100(20+10/20+100) = 100(30/120)=25 e) 100 ( 10x+1/10x+10) -- 100(200+1/200+10)= 100(201/210)

Hence choice(D) is the answer.

I think that in this scenario under pressure someone could not visualize 25% to obtain 90 and to go in the wrong way.

better an hybrid approach and in this case algebraic translation maybe is a bit safer

. 120 to 90 is just a percentage decrease from 120 to 90 120-90/120 = 1/4 =25% decrease

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

29 Dec 2013, 10:51

GyanOne wrote:

Volume now is x% greater than volume one week ago => Vnow = Vweekago (1+x/100)

If r percent of the current volume is removed, the resulting volume will be 90 percent of the volume a week ago => Vnow (1-r/100) = 0.9*Vweekago

Using the first equation, Vnow/Vweekago = (1+x/100) Putting this in the second equation, (1-r/100) (1+x/100) = 0.9 => (100 - r) (100 + x) = 9000 => r = 100 - [9000/(100+x)] => r = 100* (10+x)/(100+x)

Option D

How did you get from here to here? => r = 100 - [9000/(100+x)] => r = 100* (10+x)/(100+x)

Volume now is x% greater than volume one week ago => Vnow = Vweekago (1+x/100)

If r percent of the current volume is removed, the resulting volume will be 90 percent of the volume a week ago => Vnow (1-r/100) = 0.9*Vweekago

Using the first equation, Vnow/Vweekago = (1+x/100) Putting this in the second equation, (1-r/100) (1+x/100) = 0.9 => (100 - r) (100 + x) = 9000 => r = 100 - [9000/(100+x)] => r = 100* (10+x)/(100+x)

Option D

How did you get from here to here? => r = 100 - [9000/(100+x)] => r = 100* (10+x)/(100+x)

As per question if r percent is removed then remaining is 90 % of original. Can we infer that removed water is 10% of the original. Hence i used this equation

(r/100)*[1+x/100] V= 0.1 V..Which gave me wrong answer....Help please

The volume of water in a certain tank is x percent greater than it was one week ago. If r percent of the current volume of water in the tank is removed, the resulting volume will be 90 percent of the volume it was one week ago. what is the value of r in terms of x?

As per question if r percent is removed then remaining is 90 % of original. Can we infer that removed water is 10% of the original. Hence i used this equation

(r/100)*[1+x/100] V= 0.1 V..Which gave me wrong answer....Help please

No, that's not correct.

The volume of water one week ago = 100 (that's what I believe you call original);

The volume of water now is x=20% greater = 120.

The volume of water after removal of r% of 120 = 90.

So, as you can see r% is not 10% of 100, it's r% of 120, which result in final volume of 90.

Re: The volume of water in a certain tank is x percent greater [#permalink]

Show Tags

21 Aug 2015, 23:52

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________