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# The weight of a glass of jar is 20% of the weight of the jar

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The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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25 Nov 2012, 03:42
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45% (medium)

Question Stats:

58% (00:53) correct 42% (01:18) wrong based on 86 sessions

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The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3
[Reveal] Spoiler: OA

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Re: The weight of a glass of jar is 20% of the weight of ... [#permalink]

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25 Nov 2012, 04:25
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cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?
a.1/5
b.1/3
c.2/5
d.1/2
e.2/3

Somebody to suggest a way to solve this problem?

Let weight of jar filled with beans = 100 g
Weight of jar = 20 g
Weight of coffee beans = 80 g
Weight of jar and remaining beans = 60 g
Weight of remaining beans = 40 g

Fraction remaining = 40/80 = 1/2

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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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08 Jun 2016, 06:37
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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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08 Jun 2016, 07:04
cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3

Let weight of entire jar = $$W_T$$ and weight after removing some beans = $$W_{TN}$$
and weight of beans = $$W_B$$ and weight after removing some beans = $$W_{BN}$$
WEIGHT of jar = $$W_J = 20% of W_T$$.......
so$$W_J = \frac{W_T}{5}.........W_B = \frac{4W_T}{5}........$$
if $$W_{TN} = \frac{6W_T}{10}.................W_J$$remains constant, so$$W_{BN} = W_{TN} - W_J =\frac{6W_T}{10} - \frac{W_T}{5} = \frac{2W_T}{5}.....$$

we are looking for fraction of what is left =$$\frac{W_{BN}}{W_B} = \frac{2W_T}{5}/\frac{4W_T}{5} = \frac{1}{2}$$

D
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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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08 Jun 2016, 10:11
Initial weight of a jar with coffee beans: C
Weight of an empty jar: J = 0.2C
Initial weight of the coffee beans: = 1C - 0.2C = 0.8C

Weight of a jar with coffee beans after the removal: 0.6C
Weight of the cofee beans after the removal: 0.6C - 0.2C = 0.4C

So we know now that initially we had 0.8C and now only 0.4C: $$\frac{0.4}{0.8} = \frac{1}{2}$$

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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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08 Jun 2016, 10:54
cv3t3l1na wrote:
The weight of a glass of jar is 20% of the weight of the jar filled with coffee beans. After some of the beans have been removed, the weight of the jar and the remaining beans is 60% of the original total weight. What fraction part of the beans remain in the jar?

A. 1/5
B. 1/3
C. 2/5
D. 1/2
E. 2/3

fraction part of the beans remain in the jar=($$\frac{60}{100}$$-$$\frac{20}{100}$$)/$$\frac{80}{100}$$=$$\frac{40}{100}$$*$$\frac{100}{80}$$=$$\frac{1}{2}$$

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Re: The weight of a glass of jar is 20% of the weight of the jar [#permalink]

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18 Oct 2016, 18:04
The trick to this problem is realizing that the glass jar is representative of the glass jar + coffee beans. So once you figure out the weight of the jar, you can subtract it from the weight of jar + beans to figure out weight of the beans.

Say weight of jar + coffee = 100lb --> weight of jar = 20lb --> coffee = 80lb

weight of jar + coffee changes to 60lb --> weight of jar = 20 --> coffee = 40lb

40lb/80lb = 1/2

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Re: The weight of a glass of jar is 20% of the weight of the jar   [#permalink] 18 Oct 2016, 18:04
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