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The weights of all dishes of type X are exactly the same [#permalink]
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03 Sep 2012, 06:08
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The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectThe weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ? (1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y. Practice Questions Question: 33 Page: 277 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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SOLUTIONThe weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?Say the weight of 1 dish of type X is \(x\) and the weight of 1 dish of type Y is \(y\). The question asks whether \(x<y\). (1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y > \(3x+2y<2x+4y\) > \(x<2y\). If \(x=1\) and \(y=2\), then the answer is YES but if \(x=3\) and \(y=2\), then the answer is NO. Not sufficient. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y > \(4x+3y<3x+4y\) > \(x<y\). Sufficient. Answer: B.
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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03 Sep 2012, 06:33
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Bunuel wrote: The weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?
(1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y.
Let X & Y are respective weights of Dish 1 & Dish 2. So Question reduces to is X<Y? St 1: Insufficient: 3X + 2Y < 2X + 4Y, => X<2Y, Insufficient, X=4 & Y=5 or X=5 & Y=4 both conditions satisfy the equation. St 2: Sufficient: 4X + 3Y < 3X + 4Y => X < Y, clearly sufficient. Hence Answer is Option B.
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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07 Sep 2012, 05:48
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SOLUTIONThe weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ?Say the weight of 1 dish of type X is \(x\) and the weight of 1 dish of type Y is \(y\). The question asks whether \(x<y\). (1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y > \(3x+2y<2x+4y\) > \(x<2y\). If \(x=1\) and \(y=2\), then the answer is YES but if \(x=3\) and \(y=2\), then the answer is NO. Not sufficient. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y > \(4x+3y<3x+4y\) > \(x<y\). Sufficient. Answer: B. Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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10 May 2014, 10:40
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St I )
3x + 2y < 2x + 4y Implies x<2y . INSUFF
St II) 4x + 3y < 3x +4y, implies x < y. SUFF. Hence B



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Re: The weights of all dishes of type X are exactly the same [#permalink]
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23 May 2014, 15:29
Statement1: For those who hate picking numbers just like me: 3X + 2Y < 2X + 4Y > x<2y > x/2<y > Thus y could be less than x, equal to x or greater than x. Not sufficient St2: is quite straight forward. Sufficient B it is!
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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10 Mar 2015, 18:00
I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient.



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Re: The weights of all dishes of type X are exactly the same [#permalink]
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10 Mar 2015, 19:30
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mawus wrote: I don't get it. x<2y, if x =2, and y=3 then 2<2(3) = 2 <6 thus y is greater than x on the other hand, if x=3 and y = 2 then 3<2(2) = 3<4 thus y is still greater than x. M I missing the point ? I don't understand why you thing if x=3, and y=2 will make the first statement insufficient. Based on your example, Statement 1: X < 2Y if x=2, and y=3 3 < 2*3 true 2<3 true if x=3 and y=2 3 < 2*2 true but 3 is not < 2 we have 2 conflicting pieces of information, so Statement 1 is insufficient



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Re: The weights of all dishes of type X are exactly the same [#permalink]
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10 Mar 2015, 19:52
Thank you it make sense



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Re: The weights of all dishes of type X are exactly the same [#permalink]
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09 May 2016, 14:51
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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10 May 2016, 07:48
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectThe weights of all dishes of type X are exactly the same, and the weights of all dishes of type Y are exactly the same. Is the weight of 1 dish of type X less than the weight of 1 dish of type Y ? (1) The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. (2) The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y. Solution: We are given that we have two types of dishes, dish X and dish Y, and each dish of each type has the same weight. We are asked whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. If we let X and Y denote the weights of dishes X and Y, respectively, then we can restate the question as: Is X < Y ? Statement One Alone:The total weight of 3 dishes of type X and 2 dishes of type Y is less than the total weight of 2 dishes of type X and 4 dishes of type Y. Using the information from statement one we can set up the following inequality: 3X + 2Y < 2X + 4Y X < 2Y We see that the weight of 1 dish of type X is less than the combined weight of 2 dishes of type Y. However we can’t tell whether the weight of 1 dish of type X is less than the weight of 1 dish of type Y. This is not enough information to answer the question. We can eliminate answer choices A and D. Statement Two Alone:The total weight of 4 dishes of type X and 3 dishes of type Y is less than the total weight of 3 dishes of type X and 4 dishes of type Y. Using the information from statement two we can set up the following inequality: 4X + 3Y < 3X + 4Y X < Y We see that this answers the question. The answer is B.
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Re: The weights of all dishes of type X are exactly the same [#permalink]
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