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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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08 Nov 2016, 23:23
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82% (00:50) correct 18% (01:13) wrong based on 180 sessions
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 01:45
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 P(no blue & not red) = 4/12 =1/3 P(blue or red)= 11/3 = 2/3 D Sent from my iPhone using GMAT Club Forum mobile app



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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 02:49
Blue + Red =8 Total number of balls is 6+2+4=12 So the answer is 8/12=2/3 Answer D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 03:06
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 Total number of balls=12 Red=6 Blue=2 Green=4 P(B or R)= P(B)+P(R) P(B or R)= 6/12+ 2/12= 8/12= 2/3 Answer D



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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 03:18
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 A straight application would be.. Either blue or red means NOT green.. Prob of green = 4/12=1/3.. Prob of NOT green = 11/3=2/3.. D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 03:50
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 Probability = Favorable Outcome / Total Outcomesprobability of that it is either blue or red = (Total Blue or red balls) / Total Balls = 8/12 = 2/3 Answer: Option D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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09 Nov 2016, 07:50
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 Required Probability = \(1  \frac{4C_1}{12C_1}\) = \(1  \frac{1}{3}\) = \(\frac{2}{3}\) Hence, answer will be (D) \(\frac{2}{3}\)
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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26 Apr 2018, 23:00
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 Since its asking OR, you ADD the probability Probability of Red:6/12 Probability of Blue: 2/12 6/12 + 2/12 = 8/12 ( simplified to 2/3) D is the answer~



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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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01 Jun 2018, 23:21
Bunuel wrote: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4 Total = 12 marbles
Probability of either blue or red = 6/12 + 2/12
= 1/2 + 1/6
= 2/3
(D)
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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02 Jun 2018, 01:23
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?
A. 1/12 B. 1/4 C. 1/2 D. 2/3 E. 3/4
Ans: D Details: T= R+B+G T = 12, R=6, B=2, & G=4, P(R) = 6/12 & P (B) = 2/12 P(R or B) = P(R U B) = P(R) + P(B) = 6/12 + 2/12 = 8/12=2/3



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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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02 Jun 2018, 01:57
P(no blue & not red) = 4/12 =1/3
P(blue or red)= 11/3 = 2/3
Hence D



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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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01 Feb 2019, 22:19
Ok, I don't know whether the method applied by me is correct or not. But just putting it here for any corrections though:
1. Total no of red balls: 6
P(Red Ball): 1/6
2. Total no of blue balls: 2
P(Blue Ball): 1/2
P(R+B)= 1/6+1/2= 2/3
Is this method correct? Just wondering




There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba
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01 Feb 2019, 22:19






