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# There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba

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Math Expert
Joined: 02 Sep 2009
Posts: 58435
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 00:23
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Difficulty:

5% (low)

Question Stats:

83% (00:48) correct 17% (01:10) wrong based on 199 sessions

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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

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Posts: 215
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 02:45
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

P(no blue & not red) = 4/12 =1/3

P(blue or red)= 1-1/3 = 2/3

D

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 03:49
Blue + Red =8
Total number of balls is 6+2+4=12

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 04:06
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Total number of balls=12
Red=6 Blue=2 Green=4
P(B or R)= P(B)+P(R)
P(B or R)= 6/12+ 2/12= 8/12= 2/3
Math Expert
Joined: 02 Aug 2009
Posts: 7977
Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 04:18
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

A straight application would be..
Either blue or red means NOT green..
Prob of green = 4/12=1/3..
Prob of NOT green = 1-1/3=2/3..
D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 04:50
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Probability = Favorable Outcome / Total Outcomes

probability of that it is either blue or red = (Total Blue or red balls) / Total Balls = 8/12 = 2/3

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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09 Nov 2016, 08:50
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Required Probability = $$1 - \frac{4C_1}{12C_1}$$ = $$1 - \frac{1}{3}$$ = $$\frac{2}{3}$$

Hence, answer will be (D) $$\frac{2}{3}$$
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Posts: 19
Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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27 Apr 2018, 00:00
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Probability of Red:6/12
Probability of Blue: 2/12

6/12 + 2/12 = 8/12 ( simplified to 2/3)

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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02 Jun 2018, 00:21
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Total = 12 marbles

Probability of either blue or red = 6/12 + 2/12

= 1/2 + 1/6

= 2/3

(D)

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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02 Jun 2018, 02:23
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

Ans: D
Details:
T= R+B+G
T = 12, R=6, B=2, & G=4,
P(R) = 6/12 & P (B) = 2/12
P(R or B) = P(R U B) = P(R) + P(B) = 6/12 + 2/12 = 8/12=2/3
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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02 Jun 2018, 02:57
P(no blue & not red) = 4/12 =1/3

P(blue or red)= 1-1/3 = 2/3

Hence D
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Posts: 66
Concentration: Finance, Economics
GPA: 3.24
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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01 Feb 2019, 23:19
Ok, I don't know whether the method applied by me is correct or not. But just putting it here for any corrections though:

1. Total no of red balls: 6

P(Red Ball): 1/6

2. Total no of blue balls: 2

P(Blue Ball): 1/2

P(R+B)= 1/6+1/2= 2/3

Is this method correct? Just wondering
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba   [#permalink] 01 Feb 2019, 23:19
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