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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba

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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 08 Nov 2016, 23:23
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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 01:45
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


P(no blue & not red) = 4/12 =1/3

P(blue or red)= 1-1/3 = 2/3

D


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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 02:49
Blue + Red =8
Total number of balls is 6+2+4=12

So the answer is 8/12=2/3

Answer D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 03:06
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Total number of balls=12
Red=6 Blue=2 Green=4
P(B or R)= P(B)+P(R)
P(B or R)= 6/12+ 2/12= 8/12= 2/3
Answer D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 03:18
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


A straight application would be..
Either blue or red means NOT green..
Prob of green = 4/12=1/3..
Prob of NOT green = 1-1/3=2/3..
D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 03:50
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Probability = Favorable Outcome / Total Outcomes

probability of that it is either blue or red = (Total Blue or red balls) / Total Balls = 8/12 = 2/3

Answer: Option D
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 09 Nov 2016, 07:50
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Required Probability = \(1 - \frac{4C_1}{12C_1}\) = \(1 - \frac{1}{3}\) = \(\frac{2}{3}\)

Hence, answer will be (D) \(\frac{2}{3}\)
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 26 Apr 2018, 23:00
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Since its asking OR, you ADD the probability

Probability of Red:6/12
Probability of Blue: 2/12

6/12 + 2/12 = 8/12 ( simplified to 2/3)

D is the answer~
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 01 Jun 2018, 23:21
Bunuel wrote:
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Total = 12 marbles

Probability of either blue or red = 6/12 + 2/12

= 1/2 + 1/6

= 2/3

(D)

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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 02 Jun 2018, 01:23
There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ball is drawn from the jar, what is the probability of that it is either blue or red?

A. 1/12
B. 1/4
C. 1/2
D. 2/3
E. 3/4


Ans: D
Details:
T= R+B+G
T = 12, R=6, B=2, & G=4,
P(R) = 6/12 & P (B) = 2/12
P(R or B) = P(R U B) = P(R) + P(B) = 6/12 + 2/12 = 8/12=2/3
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Re: There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 02 Jun 2018, 01:57
P(no blue & not red) = 4/12 =1/3

P(blue or red)= 1-1/3 = 2/3

Hence D
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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba  [#permalink]

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New post 01 Feb 2019, 22:19
Ok, I don't know whether the method applied by me is correct or not. But just putting it here for any corrections though:

1. Total no of red balls: 6

P(Red Ball): 1/6

2. Total no of blue balls: 2

P(Blue Ball): 1/2

P(R+B)= 1/6+1/2= 2/3


Is this method correct? Just wondering
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There are 12 balls in a jar: 6 red, 2 blue and 4 green. If a single ba   [#permalink] 01 Feb 2019, 22:19
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