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There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th

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There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th  [#permalink]

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New post 21 Sep 2017, 00:59
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71% (01:09) correct 29% (01:26) wrong based on 66 sessions

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[GMAT math practice question]

There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and the average (arithmetic mean) of them is 100, what is the smallest possible value of t?

A. 110
B. 120
C. 130
D. 140
E. 150

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Re: There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th  [#permalink]

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New post 21 Sep 2017, 01:01
MathRevolution wrote:
[GMAT math practice question]

There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and the average (arithmetic mean) of them is 100, what is the smallest possible value of t?

A. 110
B. 120
C. 130
D. 140
E. 150


Similar question: https://gmatclub.com/forum/there-are-5- ... 28124.html
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There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th  [#permalink]

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New post 21 Sep 2017, 01:12
Since there are 5 integers(x≤y≤r≤s≤t) whose the median is 80
and we have been asked to find the smallest value of t, the minimum value us x=y=r = 80.

Since the average(arithmetic mean) of these 5 integers is 100, the sum must be equal to 500.
The value of s and t is minimum, when s=t. Let s=t=x.

2x + 240 = 500 => 2x = 260 => x = 130
Therefore, the lowest value of t = 130(Option C)
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Re: There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th  [#permalink]

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New post 24 Sep 2017, 19:25
=>

In order to have the smallest value of t, we need to maximize x, y and r. Then we have x = 80, y = 80 and r = 80. After that, in order to have the smallest value of t, we need to maximize s and so we have s = 130 and t = 130.

Ans: C
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Re: There are 5 integers and x≤y≤r≤s≤t. If the median of them is 80 and th &nbs [#permalink] 24 Sep 2017, 19:25
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