It is currently 23 Oct 2017, 08:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# There are three workers , Peter, Jamie, Vicky that can paint

Author Message
Manager
Joined: 20 Mar 2005
Posts: 201

Kudos [?]: 16 [0], given: 0

Location: Colombia, South America
There are three workers , Peter, Jamie, Vicky that can paint [#permalink]

### Show Tags

27 Nov 2006, 12:00
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There are three workers , Peter, Jamie, Vicky that can paint a room in 8, 6, 3 hours respectively, what is the ratio of the amount of work done by the slowest worker painting the room to the total amount of work?

Kudos [?]: 16 [0], given: 0

Director
Joined: 06 Feb 2006
Posts: 893

Kudos [?]: 123 [0], given: 0

### Show Tags

27 Nov 2006, 12:10
Must be 1/5.

The slowest worker's work done:1/8
Total work done: 1/8+1/6+1/3=45/72

ratio: (1/8)/(45/72)=(1/8)*(72/45)=1/5

Kudos [?]: 123 [0], given: 0

Manager
Joined: 10 Jul 2006
Posts: 72

Kudos [?]: 6 [0], given: 0

### Show Tags

27 Nov 2006, 12:16
I think it's 1/5.

The slowest worker is Peter with 8 hrs. thus, in 1 hr, he 's done 1/8 of the job.
Calculating the total amt of work done together in 1 hr: 1/8+1/6+1/3 = 30/48. and together, it will take them 1.6 hrs.

Thus, the portion that peter will get done himself is (1/8)*1.6 and 1/5 of the total work done

Kudos [?]: 6 [0], given: 0

Senior Manager
Joined: 01 Sep 2006
Posts: 301

Kudos [?]: 28 [0], given: 0

Location: Phoenix, AZ, USA

### Show Tags

27 Nov 2006, 15:51
There are three workers , Peter, Jamie, Vicky that can paint a room in 8, 6, 3 hours respectively, what is the ratio of the amount of work done by the slowest worker painting the room to the total amount of work?

Togather in 1 hr (1/8)+(1/6)+(1/3)=30/48

in 1 hour slowest does 1/8

(1/8)/(30/48)=1*48/(8*30)=6/30=1/5=20%

Kudos [?]: 28 [0], given: 0

Senior Manager
Joined: 20 Feb 2006
Posts: 373

Kudos [?]: 35 [0], given: 0

### Show Tags

28 Nov 2006, 17:32
At any given time the amount of work done by each of the workers is given by 1/8:1/6:1/3

Common denominator = 24 -----> 3/24:4/24:6/24

Slowest worker does 3/24 of work

Total work = 15/24

Ratio of slowest:total work = (3/24)/(15/24) or (3/24)*(24/15)

Cancelling out 24 gives 3/15 or 1/5

Kudos [?]: 35 [0], given: 0

28 Nov 2006, 17:32
Display posts from previous: Sort by