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There are two co-centric circles of unequal diameters. The area betwee

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There are two co-centric circles of unequal diameters. The area betwee  [#permalink]

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New post 04 Oct 2018, 23:38
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There are two co-centric circles of unequal diameters. The area between the circles is shaded. If the area of the shaded region is 3 times the area of the smaller circle, then the circumference of the larger circle is how many times the circumference of the smaller circle?

(A) 3
(B) 2.5
(C) 2
(D) √3
(E) √2

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Re: There are two co-centric circles of unequal diameters. The area betwee  [#permalink]

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New post 05 Oct 2018, 02:44
Radius of larger circle(R2) will be twice that of smaller circle(R1). Hence the circumference will be twice that of smaller circle. Answer is C

\(\pi\) (\(R2^{2}\) -\(R1^{2}\))=3\(\pi\)
solving this we get, R2=2R1

Circumference of larger circle=2\(\pi\)R2=2\(\pi\)(2R1)=2(2\(\pi\)R1)=2*Circumference of smaller circle
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Re: There are two co-centric circles of unequal diameters. The area betwee  [#permalink]

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New post 05 Oct 2018, 02:47
Bunuel wrote:
There are two co-centric circles of unequal diameters. The area between the circles is shaded. If the area of the shaded region is 3 times the area of the smaller circle, then the circumference of the larger circle is how many times the circumference of the smaller circle?

(A) 3
(B) 2.5
(C) 2
(D) √3
(E) √2



The shaded area is 3 times the area of inner circle..
So area of outer circle =4*area of inner circle....
\(π*(r_l)^2=4*π*(r_s)^2.......r_l=2r_s........2πr_l=2*(2πr_s).....\frac{2πr_l}{2πr_s}\)=2


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Re: There are two co-centric circles of unequal diameters. The area betwee &nbs [#permalink] 05 Oct 2018, 02:47
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There are two co-centric circles of unequal diameters. The area betwee

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