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# There are two right circular cylinders, A and B. The

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Joined: 04 Feb 2007
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There are two right circular cylinders, A and B. The [#permalink]

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09 Feb 2007, 22:29
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There are two right circular cylinders, A and B. The diameter of the base of the cylinder A is twice that of the base of the cylinder B. The height of the cylinder A is half that of the cylinder B. If the radius and the height of the cylinder B are r and h, respectively, what is the absolute value of the difference of the surface areas between the cylinder A and the cylinder B?

A: 4pi r^2
B: 6pi r^2
C: 8pi r^2
D: 10pi r^2
E: 14pi r^2

OA: B

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Senior Manager
Joined: 12 Mar 2006
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Schools: Kellogg School of Management

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09 Feb 2007, 23:14
B (the 2pi*r*d will get cancelled, we have two circular parts 2*(pi*4r^2 - pi*r^2) = 6*pi*r^2

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09 Feb 2007, 23:14
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# There are two right circular cylinders, A and B. The

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