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There are y bricks in a row. If one brick is to be selected at random,
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Bunuel
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There are y bricks in a row. If one brick is to be selected at random, [#permalink] New post  16 Nov 2020, 08:45
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There are y bricks in a row. If one brick is to be selected at random, the probability that it will be cracked is 3/11. In terms of y, how many of the bricks are not cracked?

A. y/11

B. 8y/11

C. 11y/8

D. 3y/11

E. 11y
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Quiz Dashboard Attempt only this question Same topic and source Same topic and difficulty Same source and difficulty Random Chronological Reverse chronological Learn more
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Re: There are y bricks in a row. If one brick is to be selected at random, [#permalink] New post  16 Nov 2020, 13:44
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Made up numbers on this one.

Assume y = 11. If y = 11 then cracked + not cracked = 11. We know that 3/11 are cracked. According to the made-up number for y (11) then we know that 3 are cracked and 8 are not cracked. Plug 11 into the answer choices to see which one gives us 8 as an answer.

A) 11/11 = 1 INCORRECT
B) 8*11 / 11 = 8 CORRECT, no need to check any of the other answers.
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CrackverbalGMAT
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Re: There are y bricks in a row. If one brick is to be selected at random, [#permalink] New post  16 Nov 2020, 17:43
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Bunuel wrote:
There are y bricks in a row. If one brick is to be selected at random, the probability that it will be cracked is 3/11. In terms of y, how many of the bricks are not cracked?

A. y/11

B. 8y/11

C. 11y/8

D. 3y/11

E. 11y




We know that P(A) + P(A') = 1

P(The brick is cracked) = 3/11

P(The brick is not cracked) = 1 - 3/11 = 8/11


\(Probability = \frac{Favorable \space Outcomes}{Total \space Outcomes}\)

The total outcomes = Total bricks = y

Let the number of bricks that have mot craxked = x

Then x/y = 8/11

x = 8y/11


Option B

Arun Kumar
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Re: There are y bricks in a row. If one brick is to be selected at random, [#permalink] New post  20 Jan 2022, 06:25
If the probability that the brick chosen will be cracked is 3/11, the probability of choosing a brick that won't be cracked is 1 - 3/11 = 8/11.
Since there are a total of y bricks, the number of bricks that are not cracked is (8/11 * y) bricks, which is 8y/11.

Hence, the answer is B.
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Re: There are y bricks in a row. If one brick is to be selected at random, [#permalink]
20 Jan 2022, 06:25
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