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There is a group of six people; among them are Mr X and Mr

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SVP
SVP
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Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 311 [0], given: 0

There is a group of six people; among them are Mr X and Mr [#permalink]

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New post 12 Jun 2004, 00:52
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There is a group of six people; among them are Mr X and Mr Y. Three persons are chosen at random without repetitions. Find the probability of choosing:

1) Mr X, but not Mr Y.
2) Both Mr X and Mr Y.
3) Neither Mr X nor Mr Y.
4) Either Mr X or Mr Y, but not both.
5) Either Mr X or Mr Y or both.

Kudos [?]: 311 [0], given: 0

Manager
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Joined: 07 May 2004
Posts: 183

Kudos [?]: 18 [0], given: 0

Location: Ukraine, Russia(part-time)
Re: some complex probability problem [#permalink]

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New post 12 Jun 2004, 01:40
stolyar wrote:
There is a group of six people; among them are Mr X and Mr Y. Three persons are chosen at random without repetitions. Find the probability of choosing:

1) Mr X, but not Mr Y.
2) Both Mr X and Mr Y.
3) Neither Mr X nor Mr Y.
4) Either Mr X or Mr Y, but not both.
5) Either Mr X or Mr Y or both.


1. C[2,4]/C[3,6] = 36/120 = 6/20 = 3/10.

2. C[1,4]/C[3,6] = 4*6*6/(6*120) = 1/5.

3. C[3,4]/C[3,6] = 1/5.

4. 2*P(X, but not Y) = 6/10 = 3/5.

5. P(X or Y, but not both) + P(both) = 3/5 + 1/5 = 4/5.

Kudos [?]: 18 [0], given: 0

SVP
SVP
User avatar
Joined: 03 Feb 2003
Posts: 1603

Kudos [?]: 311 [0], given: 0

 [#permalink]

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New post 13 Jun 2004, 13:23
Agree

(1) 0.3
(2) 0.2
(3) 0.2
(4) 0.6
(5) 0.8

Kudos [?]: 311 [0], given: 0

  [#permalink] 13 Jun 2004, 13:23
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