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# There's a basket containing 10 apples - 7 red and 3 green.

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Current Student
Joined: 31 Aug 2007
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There's a basket containing 10 apples - 7 red and 3 green. [#permalink]

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02 Apr 2008, 10:28
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There's a basket containing 10 apples - 7 red and 3 green. What's the probability that upon drawing 3 apples, we get 2 red and 1 green?

Kudos [?]: 165 [0], given: 1

Current Student
Joined: 27 Mar 2008
Posts: 415

Kudos [?]: 45 [0], given: 1

Schools: Kellogg Class of 2011
Re: PS probability--apples [#permalink]

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02 Apr 2008, 10:34
There are three different ways that the apples can be picked (RRG, RGR, GRR)

Let's look at the first case (RRG)

P(RRG) = 7/10*6/9*3/8

Since we said the order of picking apples does not matter, we will have to similarly calculate probability for RGR and GRR cases which works out to the same.

So P(2Red,1Green) = 3*(7/10*6/9*3/8) = 21/40

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Senior Manager
Joined: 20 Dec 2004
Posts: 251

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Re: PS probability--apples [#permalink]

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02 Apr 2008, 11:51
$$\frac{C_7^2*C_3^1}{C_{10}^3} = \frac{21}{40}$$
_________________

Stay Hungry, Stay Foolish

Kudos [?]: 112 [0], given: 0

Current Student
Joined: 31 Aug 2007
Posts: 367

Kudos [?]: 165 [0], given: 1

Re: PS probability--apples [#permalink]

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02 Apr 2008, 12:32
neelesh wrote:
$$\frac{C_7^2*C_3^1}{C_{10}^3} = \frac{21}{40}$$

good, agreed...can you easily solve a related problem: 7-t62090

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Re: PS probability--apples   [#permalink] 02 Apr 2008, 12:32
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# There's a basket containing 10 apples - 7 red and 3 green.

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