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There were 36.000 hardback copies of a certain novel sold [#permalink]

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02 May 2007, 21:57

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

There were 36.000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?

Re: 1000 series - dont agree with the OA ! [#permalink]

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02 May 2007, 22:23

Quote:

There were 36.000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?

Yes, the answer for (2) must be B. However, the reference key gives A !

For the 1st problem, I followed the below approach,

Hard copies - 36000

# Hard copies sold after paper back was introduced - x

hence total# hard copies sold = (36000 + x)

hence total paperbacks = 9(36000 + x)

=> 10(36000 + x) = 441000 => paper copies = 396900 ! E

What is it I am missing here ?

From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold.

The statement says from the time the first paperback copy was sold............this implies papaerback copies are 9 times the hardcopies sold after the first paperback cpy was introduced.........i.e 9x and not 9 (36000 + x)...................now u can figure out the solution.

Month Average Price per Dozen
April $1.26
May $1.20
June $1.08
The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period?
(A) $1.08
(B) $1.10
(C) $1.14
(D) $1.16
(E) $1.18

Month Average Price per Dozen April $1.26 May $1.20 June $1.08 The table above shows the average (arithmetic mean) price per dozen of the large grade A eggs sold in a certain store during three successive months. If as many dozen were sold in April as in May, and twice as many were sold in June as in April, what was the average price per dozen of the eggs sold over the three-month period? (A) $1.08 (B) $1.10 (C) $1.14 (D) $1.16 (E) $1.18

OA is D, I got E

April - number of dozen eggs sold - x - average 1.26$
May - number of dozen eggs sold - x - average 1.20$
June - number of dozen eggs sold - 2x - average 1.08$

average for three months:

(1.26x+1.2x+1.08*2x)/4x = (total price for dozen eggs/number of dozen eggs sold)

I need explanation for this too...
At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost?
(A) $0.30
(B) $0.45
(C) $0.60
(D) $0.75
(E) $0.90

Suppose H + C = 3.59; H + F = 4.40
So F - C = 4.40 - 3.59 = 0.81
Again, F = 2C.
Then, 2C - C = 0.81 & C = 0.81, and F = 2C = 1.62

I need explanation for this too... At a certain diner, a hamburger and coleslaw cost $3.59, and a hamburger and french fries cost $4.40. If french fries cost twice as much as coleslaw, how much do french fries cost? (A) $0.30 (B) $0.45 (C) $0.60 (D) $0.75 (E) $0.90

Suppose H + C = 3.59; H + F = 4.40 So F - C = 4.40 - 3.59 = 0.81 Again, F = 2C. Then, 2C - C = 0.81 & C = 0.81, and F = 2C = 1.62

Is that right?? But not in answer choice??

hi priyankur_saha@ml.com - can you please post new topics as new subject ? so every question will be separate from the others.
you will get more viewers that way.