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# This is easy, but I want to know if you have a method to

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Retired Moderator
Status: 2000 posts! I don't know whether I should feel great or sad about it! LOL
Joined: 04 Oct 2009
Posts: 1669
Location: Peru
Schools: Harvard, Stanford, Wharton, MIT & HKS (Government)
WE 1: Economic research
WE 2: Banking
WE 3: Government: Foreign Trade and SMEs
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Kudos [?]: 995 [0], given: 109

This is easy, but I want to know if you have a method to [#permalink]

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01 Sep 2010, 18:13
00:00

Difficulty:

15% (low)

Question Stats:

75% (01:55) correct 25% (00:47) wrong based on 52 sessions

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This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2
(2) x/2 = y -1
[Reveal] Spoiler: OA

_________________

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Math Expert
Joined: 02 Sep 2009
Posts: 39066
Followers: 7759

Kudos [?]: 106598 [1] , given: 11630

Re: Is x > y? [#permalink]

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01 Sep 2010, 18:35
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Expert's post
metallicafan wrote:
This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2
(2) x/2 = y -1

Is $$x>y$$?

(1) $$x=y+2$$ --> if you just read what is written you'll get "$$x$$ is 2 more than $$y$$", so $$x$$ is more than $$y$$. Sufficient.

Or you can substitute $$x$$ in the question: is $$x>y$$? --> question becomes: is $$y+2>y$$? is $$2>0$$? YES, 2 is more than 0. So the answer to the question is YES. Sufficient.

(2) $$\frac{x}{2}=y-1$$ --> $$x=2y-2$$ --> substitute $$x$$ in the question: is $$x>y$$? --> question becomes: is $$2y-2>y$$? is $$y>2$$? We don't know that, hence this statement is not sufficient.

As for number plugging:
On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.

Try $$x=0$$ then $$y=1$$ and the answer to the question is NO;
Increase $$x$$: try $$x=10$$ then $$y=6$$ and the answer to the question is YES.

Two different answer, hence not sufficient.

Answer: A.

Hope it helps.
_________________
Retired Moderator
Status: 2000 posts! I don't know whether I should feel great or sad about it! LOL
Joined: 04 Oct 2009
Posts: 1669
Location: Peru
Schools: Harvard, Stanford, Wharton, MIT & HKS (Government)
WE 1: Economic research
WE 2: Banking
WE 3: Government: Foreign Trade and SMEs
Followers: 103

Kudos [?]: 995 [0], given: 109

Re: Is x > y? [#permalink]

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01 Sep 2010, 18:42
Bunuel wrote:
metallicafan wrote:
This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2
(2) x/2 = y -1

Is $$x>y$$?

(1) $$x=y+2$$ --> if you just read what is written you'll get "$$x$$ is 2 more than $$y$$", so $$x$$ is more than $$y$$. Sufficient.

Or you can substitute $$x$$ in the question: is $$x>y$$? --> question becomes: is $$y+2>y$$? is $$2>0$$? YES, 2 is more than 0. So the answer to the question is YES. Sufficient.

(2) $$\frac{x}{2}=y-1$$ --> $$x=2y-2$$ --> substitute $$x$$ in the question: is $$x>y$$? --> question becomes: is $$2y-2>y$$? is $$y>2$$? We don't know that, hence this statement is not sufficient.

As for number plugging:
On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.

Try $$x=0$$ then $$y=1$$ and the answer to the question is NO;
Increase $$x$$: try $$x=10$$ then $$y=6$$ and the answer to the question is YES.

Two different answer, hence not sufficient.

Answer: A.

Hope it helps.

Thanks Bunuel!, you are the real Master!
_________________

"Life’s battle doesn’t always go to stronger or faster men; but sooner or later the man who wins is the one who thinks he can."

My Integrated Reasoning Logbook / Diary: http://gmatclub.com/forum/my-ir-logbook-diary-133264.html

GMAT Club Premium Membership - big benefits and savings

Manager
Joined: 17 Mar 2010
Posts: 182
Followers: 3

Kudos [?]: 186 [0], given: 9

Re: Is x > y? [#permalink]

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02 Sep 2010, 01:06
substitution is best in this case
Re: Is x > y?   [#permalink] 02 Sep 2010, 01:06
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# This is easy, but I want to know if you have a method to

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