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Three bodies A, B and C start moving around a circular track [#permalink]

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27 Apr 2012, 14:07

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Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

Re: Three bodies A, B and C start moving around a circular track [#permalink]

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29 Aug 2012, 08:34

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Speed of A,B and C are 3, 5, 9 m/s respectively. Considering A&B: Speed of B is (5-3)=2 m/s more than that of A. So with this relative speed it will take 60/2= 30 sec to cover the full length.

Considering B&C: Relative speed is (9-5)=4 m/s. So, B&C will meet after every 60/4=15 sec.

Considering A&C: Relative speed is (9-3)=6 m/s. So, A&C will meet after every 60/6=10 sec.

The time when all three will meet together is the LCM of values 30, 15 and 10. That is 30. Because 30=30*1 ( So A,B meet) 30=15*2 (So, B,C meet) 30=10*3 (So, A,C meet)

So, after 30 sec they will meet again.

A Follow-up Question: When will A,B and C meet together at the start point? _________________

My mantra for cracking GMAT: Everyone has inborn talent, however those who complement it with hard work we call them 'talented'.

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Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

A - 3 m/s, B - 5 m/s, C - 9 m/s

When will they meet if they are moving in the same direction? When B covers one (or multiple) complete circle more than A and C also covers one (or multiple) complete circle more than A.

B's speed is 2 m/s more than A so he will take 60/2 = 30 s to complete one full circle more than A. In 60 secs he will cover 2 circles more than A and so on...

C's speed is 6 m/s more than A so he will take 60/6 = 10 s to complete one full circle more than A. In 20 secs he will cover 2 circles more than A and in 30 sec he will cover 3 circles more than A.

So in 30 s, all A, B and C will be at the same point. Answer A
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Re: Three bodies A, B and C start moving around a circular track [#permalink]

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25 Aug 2012, 11:37

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Hi Karishma,

After calculating Relative speed of B & C over A. We can take LCM of time taken to complete one round by B & C to find out when all three will meet. This shortcut is preferred once anyone has mastered the logic as suggested by karishma
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Re: Three bodies A, B and C start moving around a circular track [#permalink]

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25 Aug 2012, 12:23

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vdadwal wrote:

Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

If they all meet after T seconds, it means they covered the distances 3T, 5T, and 9T respectively. Since they all arrive to the same spot, it means that the differences taken pairwise between the distances must be positive integer multiples of the length of the track, which is 60m. So, 2T, 4T, and 6T must all be multiples of 60. 2T multiple of 60 means T multiple of 30. The smallest T with this property is 30 and is on the list of answers.

Answer A.
_________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: Three bodies A, B and C start moving around a circular track [#permalink]

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19 Aug 2013, 14:01

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Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

From the onset I kind of figured you could solve with LCM's but I wasn't entirely sure why. I tried solving by figuring out how long it would take each of them to make one complete revolution and keep counting until their times aligned but I think that is incorrect because we're trying to figure out how long it takes for them to "meet up" we cannot solve that way. Is this correct?

If that is the case, then we need to figure out their relative speeds to determine when each body (let's call them A, B, C for the slow, medium and fast objects respectively) reaches the other.

B's relative rate to A is 5-3 = 2m/second so it takes B 30 seconds to move 60 meters away from A. In other words, at the 30 second mark, A and B are next to one another. A has traveled 90 meters and B has traveled 150 meters.

C's relative rate to A is 9-3 = 6m/second so it takes C 10 seconds to move 60 meters away from A. Every 10 seconds, it moves 60 meters (one full revolution) away from A. In 30 seconds (the time it takes A and B to meet up) it is 3 full revolutions ahead of A but is also next to it on the circle.

Re: Three bodies A, B and C start moving around a circular track [#permalink]

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27 Apr 2012, 15:07

For this question , we will start with the body who is the slowest i.e. 3m/sec.

Since the questions asks us when all the three bodies are going to meet , so assume the time t is reqduired to do this Distance travelled by I body: 3t Distance travelled by II body: 5t Distance travelled by III body: 9t

the distances should be equal to meet , and that is possible because of a circular track , length of the track: 60m

Keep this is mind , for circular track The point on the circular track = n * length of the track + remaining distance where n is a positive integer

Like if someone travels from point Z on the track 200 m then actually he is far from point Z by 20m . As ,200 = 3*60 +20

Now i inserted the values : A: 30 secs I=3*30=90 = one length of track +30 ; II=5*30=150 = 2 lenth of track + 30; III= 9*30 =270 = 4 lenth of track +30;

so everyone is at 30 m after 30 secs. Hence A is the answer.

After calculating Relative speed of B & C over A. We can take LCM of time taken to complete one round by B & C to find out when all three will meet. This shortcut is preferred once anyone has mastered the logic as suggested by karishma

Yes, you are right. You get that the time taken by B to complete one extra circle is 30 secs and time taken by C to complete one extra circle is 10 secs. You take their LCM which is 30 secs. The theory explains why you should take the LCM.
_________________

Re: Three bodies A, B and C start moving around a circular track [#permalink]

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18 Aug 2013, 01:34

VeritasPrepKarishma wrote:

vdadwal wrote:

Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

A - 3 m/s, B - 5 m/s, C - 9 m/s

When will they meet if they are moving in the same direction? When B covers one (or multiple) complete circle more than A and C also covers one (or multiple) complete circle more than A.

B's speed is 2 m/s more than A so he will take 60/2 = 30 s to complete one full circle more than A. In 60 secs he will cover 2 circles more than A and so on...

C's speed is 6 m/s more than A so he will take 60/6 = 10 s to complete one full circle more than A. In 20 secs he will cover 2 circles more than A and in 30 sec he will cover 3 circles more than A.

So in 30 s, all A, B and C will be at the same point. Answer A

Hi Karishma

I have lost control over my understanding though u mentioned very clearly. Requesting you to again depicts the same for me.

Also the theory behind the logic and any other question of similar kind.

Re: Three bodies A, B and C start moving around a circular track [#permalink]

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18 Aug 2013, 03:11

Bluelagoon wrote:

Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

i like to back solve it: (it takes at most 40 seconds) i explained my way below: For circular distance of 60 meter, 60,120,180,240 all end in the same point

for body A , 30 * 3 = 90 m = 60 + 30 m (so 30m ahead from the starting point) for body, B, 30 * 5 = 150 m = 120 + 30 m (so 30m ahead from the starting point) for body C, 30 * 9 = 270 m = 240 + 30 m (so 30m ahead from the starting point) Everyone 30m ahead of the starting point after 30 sec.

i am lucky enough that the 1st answer satisfies my findings.
_________________

Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

A - 3 m/s, B - 5 m/s, C - 9 m/s

When will they meet if they are moving in the same direction? When B covers one (or multiple) complete circle more than A and C also covers one (or multiple) complete circle more than A.

B's speed is 2 m/s more than A so he will take 60/2 = 30 s to complete one full circle more than A. In 60 secs he will cover 2 circles more than A and so on...

C's speed is 6 m/s more than A so he will take 60/6 = 10 s to complete one full circle more than A. In 20 secs he will cover 2 circles more than A and in 30 sec he will cover 3 circles more than A.

So in 30 s, all A, B and C will be at the same point. Answer A

Hi Karishma

I have lost control over my understanding though u mentioned very clearly. Requesting you to again depicts the same for me.

Also the theory behind the logic and any other question of similar kind.

Three bodies A, B and C start moving around a circular track of length 60m from the same point simultaneously in the same direction at speeds of 3 m/s, 5 m/s and 9 m/s respectively. When will they meet for the first time after they started moving?

A. 30 seconds B. 60 seconds C. 15 seconds D. 10 seconds E. 25 seconds

From the onset I kind of figured you could solve with LCM's but I wasn't entirely sure why. I tried solving by figuring out how long it would take each of them to make one complete revolution and keep counting until their times aligned but I think that is incorrect because we're trying to figure out how long it takes for them to "meet up" we cannot solve that way. Is this correct?

If that is the case, then we need to figure out their relative speeds to determine when each body (let's call them A, B, C for the slow, medium and fast objects respectively) reaches the other.

B's relative rate to A is 5-3 = 2m/second so it takes B 30 seconds to move 60 meters away from A. In other words, at the 30 second mark, A and B are next to one another. A has traveled 90 meters and B has traveled 150 meters.

C's relative rate to A is 9-3 = 6m/second so it takes C 10 seconds to move 60 meters away from A. Every 10 seconds, it moves 60 meters (one full revolution) away from A. In 30 seconds (the time it takes A and B to meet up) it is 3 full revolutions ahead of A but is also next to it on the circle.

ANSWER A. 30 seconds.

LCM of time works for a question of a different type: When will they meet for the first time AT THE STARTING POINT after they started moving?

Time take by A to cover a circle = 60/3 = 20 sec Time taken by B to cover a circle = 60/5 = 12 sec Time taken by C to cover a circle = 60/9 sec

So every 20 sec, A will be at the starting point. Every 12 secs B will be at the starting point. Every 60/9 sec, C will be at the starting point.

Taking their LCM, we get 60. So every 60 sec, all three will be at the starting point. All meet for the first time at the starting point after they start moving after 60 sec.
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Re: Three bodies A, B and C start moving around a circular track [#permalink]

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