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# Three Children Alice, Brain & Chris have a total of

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Manager
Joined: 27 May 2010
Posts: 197

Kudos [?]: 71 [0], given: 3

Three Children Alice, Brain & Chris have a total of [#permalink]

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07 Aug 2010, 22:30
00:00

Difficulty:

35% (medium)

Question Stats:

73% (00:47) correct 27% (00:56) wrong based on 11 sessions

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Three Children Alice, Brain & Chris have a total of $1.20 between them. Does Chris have the most money? i) Alice has 35 cents. ii) Chris has 40 cents. I'm confused with the explanation given in the book. Is B actually right as they claim? The best option B can give you is all three have the same amount of money, i.e$0.40

Can someone help!!!
[Reveal] Spoiler: OA

Kudos [?]: 71 [0], given: 3

GMAT Tutor
Joined: 24 Jun 2008
Posts: 1339

Kudos [?]: 1951 [1], given: 6

Re: Kaplan 800 DS Question [#permalink]

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08 Aug 2010, 00:52
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Expert's post
qweert wrote:
Three Children Alice, Brain & Chris have a total of $1.20 between them. Does Chris have the most money? i) Alice has 35 cents. ii) Chris has 40 cents. I'm confused with the explanation given in the book. Is B actually right as they claim? The best option B can give you is all three have the same amount of money, i.e$0.40

Can someone help!!!

With Statement 2, either they each have different amounts of money, in which case we can be absolutely certain that Chris does *not* have the most money, or they each have the same amount of money - 40 cents each. Then the question becomes, essentially, "If Alice, Brian and Chris each have 40 cents, who has the most money?" I have no idea what that question even means. Is the answer 'none of them', or is it 'all of them'? Can we say that Chris has the most money, since no one has less than he has, or does Chris not have the most because no one has more than he has? That's not a question of mathematics; it's a question of semantics, and that's not what the GMAT is testing.

You could justify answer choice B here, and you could justify answer choice C here. I don't think it's at all a good question, and it just seems like an example of a prep company trying too hard to be 'tricky'. You'll never find a question so ambiguous on the real GMAT.
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Kudos [?]: 1951 [1], given: 6

Manager
Joined: 27 May 2010
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Kudos [?]: 71 [0], given: 3

Re: Kaplan 800 DS Question [#permalink]

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08 Aug 2010, 04:17
Thank you..

Even i though the question was too ambiguous...

Kudos [?]: 71 [0], given: 3

Intern
Joined: 05 Nov 2009
Posts: 32

Kudos [?]: 4 [1], given: 3

Re: Kaplan 800 DS Question [#permalink]

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08 Aug 2010, 17:19
1
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I think B gives enough information to establish the answer to this yes/no D.S. question. If It's given that he has $0.40, either 1) they all of same amount of money or 2) someone has less and someone has more money that he does. Either way, the answer is "no", Chris doesn't have the MOST amount of money. Kudos [?]: 4 [1], given: 3 Senior Manager Status: Time to step up the tempo Joined: 24 Jun 2010 Posts: 404 Kudos [?]: 247 [0], given: 50 Location: Milky way Schools: ISB, Tepper - CMU, Chicago Booth, LSB Re: Kaplan 800 DS Question [#permalink] ### Show Tags 11 Aug 2010, 19:16 qweert wrote: Three Children Alice, Brain & Chris have a total of$1.20 between them. Does Chris have the most money?

i) Alice has 35 cents.
ii) Chris has 40 cents.

I'm confused with the explanation given in the book.

Is B actually right as they claim?

The best option B can give you is all three have the same amount of money, i.e $0.40 Can someone help!!! Statement B: Choices for the money (in cents) could be Alice -- Brain -- Chris ------ Does chris have the most money 0 80 40 No 80 0 40 No 60 20 40 No 10 70 40 No 40 40 40 No To make Chris have the most money, the distribution should be 39 39 40 -- Yes, but the some does not match up to 120 cents. Hence answer B alone is sufficient. _________________ Support GMAT Club by putting a GMAT Club badge on your blog Kudos [?]: 247 [0], given: 50 Manager Joined: 21 May 2011 Posts: 241 Kudos [?]: 271 [0], given: 8 Three children, Alice, Brian, and Chris have a total of [#permalink] ### Show Tags 24 Jul 2011, 15:30 1 This post was BOOKMARKED Three children, Alice, Brian, and Chris have a total of$1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.

Kudos [?]: 271 [0], given: 8

Intern
Joined: 17 May 2009
Posts: 30

Kudos [?]: 105 [0], given: 0

Location: United States
GMAT 1: 770 Q51 V44
GPA: 3.62
WE: Corporate Finance (Manufacturing)
Re: DS - 700 level - money [#permalink]

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24 Jul 2011, 20:01
bschool83 wrote:
Three children, Alice, Brian, and Chris have a total of $1.20 between them. Does Chris have the most money? (1) Alice has 35 cents. (2) Chris has 40 cents. $$A + B + C = 120$$, is $$C > A$$ and $$C>B$$? 1) $$A = 35$$, therefore $$B + C = 120 - 35 = 85$$. It could be that $$C = 84$$ and $$A = 1$$, or that $$C = 1$$ and $$B = 84$$. $$C$$ is greater than both $$A$$ and $$B$$ in one scenario, but not in the other. Insufficient. 2) $$C = 40$$, therefore $$A + B = 120 - 40 = 80$$. This means that the average of $$A$$ and $$B$$ is $$40$$, and either $$A = B = 40$$, or $$A > 40 > B$$, or $$B > 40 > A$$. Either way, $$C$$ is NOT greater than both $$A$$ and $$B$$. Sufficient. [Reveal] Spoiler: B Kudos [?]: 105 [0], given: 0 Intern Joined: 27 Mar 2012 Posts: 2 Kudos [?]: [0], given: 0 GMAT 1: 690 Q43 V41 GPA: 3.65 WE: Sales (Computer Software) Re: Three children, Alice, Brian, and Chris have a total of [#permalink] ### Show Tags 27 Mar 2012, 22:11 I have to disagree. In the case where each have 40c ie you have a set (40, 40, 40) they each individually have the most (ie the highest value = 40) and it so happens they each individually have the least, again 40. Since this provides two cases, Brian having the most when they all share the most (similar to tied for 1st place - they are equally best) and Brian not having the most when any other values are chosen, one requires both (1) and (2) to determine if Chris does/doesn't have the most. Clearly this is a definition debate around "most" and ties for most, and the question would likely (hopefully) be thrown out by the gmac folks! Kudos [?]: [0], given: 0 Math Expert Joined: 02 Sep 2009 Posts: 41871 Kudos [?]: 128551 [1], given: 12180 Re: Three children, Alice, Brian, and Chris have a total of [#permalink] ### Show Tags 28 Mar 2012, 00:59 1 This post received KUDOS Expert's post bschool83 wrote: Three children, Alice, Brian, and Chris have a total of$1.20 between them. Does Chris have the most money?

(1) Alice has 35 cents.

(2) Chris has 40 cents.

This is a poor quality question because of its ambiguous wording.

For statement (2) if all 3 children have 40 cents, does that mean that all of them have the most money or none of them have the most money? How are we supposed to treat ties?

So, I'd advice not to study this question at all.
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Kudos [?]: 128551 [1], given: 12180

Intern
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Re: Three children, Alice, Brian, and Chris have a total of [#permalink]

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29 Mar 2012, 03:58
Answer should be C, what is the OA?

The explanation is in either of the case A or B, Chris may or may not have the most money.

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Math Expert
Joined: 02 Sep 2009
Posts: 41871

Kudos [?]: 128551 [1], given: 12180

Re: Three children, Alice, Brian, and Chris have a total of [#permalink]

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29 Mar 2012, 05:16
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Expert's post
monu1101 wrote:
Answer should be C, what is the OA?

The explanation is in either of the case A or B, Chris may or may not have the most money.

Welcome to GMAt Club.

Please check this: three-children-alice-brian-and-chris-have-a-total-of-117635.html#p1066131 So as you can see it's a poorly designed question, and one can justify B as well as C for it, and that's exactly why this kind of question has zero chances of appearing on the real test.

By the way the OA for this question is B, though it's completely irrelevant since as discussed the question is quite ambiguous.

Hope it helps.
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Kudos [?]: 128551 [1], given: 12180

Re: Three children, Alice, Brian, and Chris have a total of   [#permalink] 29 Mar 2012, 05:16
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