Looking at the answer choices, the most logically answer will be E.

When 3 dice are rolled the lowest score one can get is 3 and the highest will be 18. Which means that there are 16 different scores that you can get. The only scores lower than 6 are 5, 4 and 3. Which means that you have \(\frac{13}{16}\) scores are 6 or higher. Looking at the choices, only B and E seem like plausible answers. B would be just under 50% chance, which is far too low and E is around a 95% chance.

So answer E.

Solving the question mathematically:

Reverse method. The only scores lower than 6 are 3, 4 and 5. Find the probability of scoring one of those scores and subtract from 1, to find the probability of scoring 6 or higher.

Total possible outcomes rolling 3 dice: \(6*6*6 = 216\)

Score of 3: Only way to score 3 is with three 1's. There is only 1 way to roll three 1's.

Score of 4: Can only be scored by rolling two 1's and one 2. This can be done in 3 different ways (1-1-2, 1-2-1, 2-1-1).

Score of 5: Can be scored either by rolling two 1's and a single 3, or two 2's and a single 1. Each of which can occur in three ways, so there are 6 ways in total.


Probability of rolling a score under 6: \(\frac{1+3+6}{216}\)

\(\frac{10}{216}\)

Probability or rolling a score of 6 and higher: \(1- \frac{10}{216}\)

\(\frac{206}{216}\)

\(\frac{103}{108}\)

Answer E