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# Three fair dice were thrown simultaneously. One of the

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Manager
Joined: 28 Feb 2003
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Three fair dice were thrown simultaneously. One of the [#permalink]

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19 May 2003, 23:35
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Three fair dice were thrown simultaneously. One of the number was 4. Find the sum of all the three numbers.

1) the sum of two of the numbers was 10
2) the sum of two of the numbers was 11
Manager
Joined: 28 Feb 2003
Posts: 100
Followers: 1

Kudos [?]: 9 [0], given: 0

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19 May 2003, 23:53
B it is

was it easy to spot the trick?
SVP
Joined: 03 Feb 2003
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20 May 2003, 00:03
About 2 minutes. You were right by naming the second set as the second one. If it were the first, it would be easier to crack.

Other people are invited to discuss. The problem is interesting!
Manager
Joined: 12 Mar 2003
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20 May 2003, 05:05
What's the trick ?

only 2 numbers on a dice can add to 11 ?
Manager
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20 May 2003, 05:23
for 2) 4 cannot be one of the 2 dice as 6 is max. therefore sum of three is 15 ?
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20 May 2003, 05:42
Yes, the trick is that 6 is a maximal number.
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18 Mar 2006, 22:43
Fortunately, I had a dice in mind while thinking on this.

"B" it is!
Manager
Joined: 12 Feb 2006
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19 Mar 2006, 09:41
i think i'm missing the trick

if one of the numbers is 4..

1) sum is 10 ( can't it be two 5's??
2) sum is 11 ( 6 & 5)

Can someone explain this
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19 Mar 2006, 09:41
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