Last visit was: 25 Apr 2024, 03:43 It is currently 25 Apr 2024, 03:43

Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
SORT BY:
Date
Tags:
Show Tags
Hide Tags
User avatar
Intern
Intern
Joined: 02 Jun 2011
Status:pursuing a dream
Posts: 32
Own Kudos [?]: 271 [8]
Given Kudos: 10
Schools:MIT Sloan (LGO)
Send PM
User avatar
Intern
Intern
Joined: 24 Apr 2011
Status:Dreaming High
Posts: 41
Own Kudos [?]: 16 [3]
Given Kudos: 14
Location: India
Concentration: Operations, Strategy
GMAT 1: 720 Q50 V36
GPA: 3.28
WE:Project Management (Manufacturing)
Send PM
User avatar
Manager
Manager
Joined: 04 Jun 2011
Posts: 99
Own Kudos [?]: 164 [0]
Given Kudos: 21
Send PM
avatar
Intern
Intern
Joined: 04 Oct 2011
Posts: 5
Own Kudos [?]: 30 [0]
Given Kudos: 3
Send PM
Re: Three machines working in parallel [#permalink]
all three working together it is 24


so 1/K+1/M+1/P = 1/24

1. 1/M+1/P = 1/36

Applying this we can find 1/k

2. WE cannot fin 1/K with this

Ans A
User avatar
Manager
Manager
Joined: 08 Jun 2011
Posts: 62
Own Kudos [?]: 76 [0]
Given Kudos: 65
Send PM
Re: Three machines working in parallel [#permalink]
Depaulian wrote:
From the data provided in the Q

1/k + 1/m + 1/p = 1/24


(1) says
1/m + 1/ p = 1/36
which along with the eq from the Qs, gives
1/k = 1/24 - 1/36 = 1/72

means k will take 72 mins ,working alone at its constant rate, to complete the task

(2) says
1/k + 1/p = 1/48
from this data , we can ind the working rate of m/c M.


So (1) alone is sufficient



Can someone please explain the reasoning behind flipping them like that?

I know that the amount of work produced is Rate * time = work. How is that used in this answer?

Thank you
User avatar
Manager
Manager
Joined: 05 Mar 2011
Posts: 78
Own Kudos [?]: 603 [0]
Given Kudos: 3
Send PM
Re: Three machines working in parallel [#permalink]
viks4gmat wrote:
buddy... in the exam you wouldnt want to actually sit and <solve> such problems. In some DS questions u can conclude without actually solving them... this is one such type of a problem

if u really want a detailed explanation, here it is...

let mc K do the task individually in k mins
similarly P in p mins
and M in m mins

so K's work in 1 min is 1/k
M's work similarly is 1/m
and P's is 1/p

since working together they can complete the work in 24 mins, they complete 1/24th work in 1 min

= > 1/k + 1/m + 1/p = 1/24 ------ (1)

the remainder of the part, is pretty much the same as Depaulian has suggested. hence ans is A



This is a gr8 explanation- thanks i missed the qs
User avatar
Manager
Manager
Joined: 13 May 2011
Posts: 144
Own Kudos [?]: 508 [1]
Given Kudos: 11
Concentration: Supply Chain, Logistics
WE 1: IT 1 Yr
WE 2: Supply Chain 5 Yrs
Send PM
Re: Three machines, K, M, and P, working simultaneously and [#permalink]
1
Bookmarks
1/k+1/M+1/p=1/24. K=?

Statement 1: we have value for 1/M+1/P. Can solve for K. Sufficient.
Statement 2: we have value for 1/K+1/P. Can solve for M but not for K. Not sufficient.
Math Expert
Joined: 02 Sep 2009
Posts: 92912
Own Kudos [?]: 618900 [4]
Given Kudos: 81595
Send PM
Re: Three machines, K, M, and P, working simultaneously and [#permalink]
2
Kudos
2
Bookmarks
Expert Reply
Three machines, K, M, and P, working simultaneously and independently at their respective constant rates, can complete a certain task in 24 minutes. How long does it take Machine K, working alone at its constant rate, to complete the task?

Say k, m, and p are the numbers of minutes machines K, M, and P take, respectively, to complete the task. Then we have that \(\frac{1}{k}+\frac{1}{m}+\frac{1}{p}=\frac{1}{24}\).

(1) Machines M and P, working simultaneously and independently at their respective constant rates, can complete the task in 36 minutes --> \(\frac{1}{m}+\frac{1}{p}=\frac{1}{36}\), thus \(\frac{1}{k}+\frac{1}{36}=\frac{1}{24}\) --> we can find the value of \(k\). Sufficient.

(2) Machines K and P, working simultaneously and independently at their respective constant rates, can complete the task in 48 minutes --> \(\frac{1}{k}+\frac{1}{p}=\frac{1}{48}\). The value of k cannot be determined from the data we have. Not sufficient.

Answer: A.

OPEN DISCUSSION OF THIS QUESTION IS HERE: three-machines-k-m-and-p-working-simultaneously-and-143489.html

ALL OG13 QUESTIONS WITH SOLUTIONS: the-official-guide-quantitative-question-directory-143450.html
GMAT Club Bot
Re: Three machines, K, M, and P, working simultaneously and [#permalink]
Moderator:
Math Expert
92912 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne