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# Three squares R, S, T are shown above. The area of R is twice the area

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Math Expert
Joined: 02 Sep 2009
Posts: 41886

Kudos [?]: 128688 [0], given: 12182

Three squares R, S, T are shown above. The area of R is twice the area [#permalink]

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22 Sep 2017, 00:37
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Question Stats:

100% (01:00) correct 0% (00:00) wrong based on 10 sessions

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Three squares R, S, T are shown above. The area of R is twice the area of S, and the area of S is twice the area of T. If the area of S is 1, what is the sum of the areas of all the three squares?

(A) 2 1/2
(B) 3 1/2
(C) 4
(D) 5 1/4
(E) 6

[Reveal] Spoiler:
Attachment:

2017-09-20_1022_003.png [ 11.76 KiB | Viewed 223 times ]
[Reveal] Spoiler: OA

_________________

Kudos [?]: 128688 [0], given: 12182

Senior Manager
Joined: 02 Jul 2017
Posts: 252

Kudos [?]: 59 [0], given: 59

Location: India
Re: Three squares R, S, T are shown above. The area of R is twice the area [#permalink]

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22 Sep 2017, 01:49
Bunuel wrote:

Three squares R, S, T are shown above. The area of R is twice the area of S, and the area of S is twice the area of T. If the area of S is 1, what is the sum of the areas of all the three squares?

(A) 2 1/2
(B) 3 1/2
(C) 4
(D) 5 1/4
(E) 6

[Reveal] Spoiler:
Attachment:
2017-09-20_1022_003.png

Bunuel : I think you have attached wrong image with the question. Attached image contains a square, triangle and pentagon.

Well here we don't require the images as give R,S and T are squares.

Solution:
Three squares R, S, T are shown above. The area of R is twice the area of S, and the area of S is twice the area of T. If the area of S is 1, what is the sum of the areas of all the three squares?

R =2S and S = 2T
Given area of square S =1 => $$R=2$$ and $$T=\frac{1}{2}$$
$$R+S+T = 1+2+\frac{1}{2} = 7/2 = 3\frac{1}{2}$$

Kudos [?]: 59 [0], given: 59

Re: Three squares R, S, T are shown above. The area of R is twice the area   [#permalink] 22 Sep 2017, 01:49
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