It is currently 29 Jun 2017, 01:03

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Tom and Linda stand at point A. Linda begins to walk in a

Author Message
TAGS:

### Hide Tags

Manager
Joined: 09 Apr 2010
Posts: 79
Tom and Linda stand at point A. Linda begins to walk in a [#permalink]

### Show Tags

02 May 2010, 01:11
3
KUDOS
19
This post was
BOOKMARKED
00:00

Difficulty:

95% (hard)

Question Stats:

48% (03:20) correct 52% (02:02) wrong based on 673 sessions

### HideShow timer Statistics

Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?

A. 60
B. 72
C. 84
D. 90
E. 108
[Reveal] Spoiler: OA

Last edited by VeritasPrepKarishma on 11 Sep 2012, 21:07, edited 1 time in total.
(Edited the OA)
CEO
Status: Nothing comes easy: neither do I want.
Joined: 12 Oct 2009
Posts: 2783
Location: Malaysia
Concentration: Technology, Entrepreneurship
Schools: ISB '15 (M)
GMAT 1: 670 Q49 V31
GMAT 2: 710 Q50 V35
Re: Tom and Linda stand at point A. [#permalink]

### Show Tags

02 May 2010, 04:57
11
KUDOS
1
This post was
BOOKMARKED
neoreaves wrote:
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?

a)60
b)72
c)84
d)90
e)108

IMO E - 108

Case 1: $$6*t1 = \frac{1}{2}* (t1+1) * 2 => t1 = \frac{1}{5}$$ hour = 12 minutes

Case 2: $$6*t2 = 2* (t2+1) * 2 => t1 = 2 = 120$$minutes

Difference = 120-12 = 108 minutes
_________________

Fight for your dreams :For all those who fear from Verbal- lets give it a fight

Money Saved is the Money Earned

Jo Bole So Nihaal , Sat Shri Akaal

GMAT Club Premium Membership - big benefits and savings

Gmat test review :
http://gmatclub.com/forum/670-to-710-a-long-journey-without-destination-still-happy-141642.html

Intern
Joined: 28 Feb 2010
Posts: 9
Re: Tom and Linda stand at point A. [#permalink]

### Show Tags

05 May 2010, 04:20
I quite did not understand the solution. Could you please explain, Majorshareholder. Thanks,
VP
Joined: 17 Feb 2010
Posts: 1489
Re: Tom and Linda stand at point A. [#permalink]

### Show Tags

03 Sep 2010, 14:12
When I solve this problem by picking numbers for total distance (not algebraically as gurpreet showed) I get different answer.....
Manager
Joined: 17 Mar 2010
Posts: 183
Re: Tom and Linda stand at point A. [#permalink]

### Show Tags

05 Sep 2010, 00:27
D = TS where D=distance, T=Time and S=Speed
To travel half distance, (2+2T) = 6T ==> T = 1/5 ==> 12 minutes
To travel double distance, 2(2+2T) = 6T ==> 2 ==> 120 minutes
Difference, 108 minutes
Intern
Joined: 05 Feb 2011
Posts: 10
Tom and Linda stand at point A. Linda begins to walk in a [#permalink]

### Show Tags

05 Apr 2011, 19:29
Another version of the same question

Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?

A. 60
B. 72
C. 84
D. 90
E. 120

Last edited by VeritasPrepKarishma on 11 Sep 2012, 21:09, edited 1 time in total.
Edited to avoid confusion
Manager
Joined: 09 Aug 2010
Posts: 107
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

05 Apr 2011, 19:44
3
KUDOS
2
This post was
BOOKMARKED
HelloKitty wrote:
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?

A) 60
B) 72
C) 84
D) 90
E) 120

My Solution:
Lrate: 2mph
Trate: 6mph

Ltime: t + 1 hour
Ttime: t hour

Ldistance: 2t + 2
Tdistance: 6t

T to cover L's distance: 2t + 2 = 6t, t = 1/2 hour
T to cover 2L distance: 2 (2t +2) = 6t, 2t = 4, t = 2 hours

2 - 1/2 = 1.5 hours = 90 minutes
Director
Status: Impossible is not a fact. It's an opinion. It's a dare. Impossible is nothing.
Affiliations: University of Chicago Booth School of Business
Joined: 03 Feb 2011
Posts: 900
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

05 Apr 2011, 19:58
This approach is same as mine. But there seems to be a gap between our thinking and Ron's although the numerical answer is same. See this article - http://www.manhattangmat.com/forums/wal ... t6180.html. Couldn't put this in right perspective

Quote:

first situation:
2t = 6(t - 1)
2t = 6t - 6
6 = 4t
3/2 = t
(notice this is the same as above: the two times are t = 3/2 and (t - 1) = 1/2. in the above, they were t = 1/2 and (t + 1) = 3/2.)

second situation:
2(2t) = 6(t - 1)
4t = 6t - 6
6 = 2t
3 = t
(notice this is the same as above: the two times are t = 3 and (t - 1) = 2. in the above, they were t = 2 and (t + 1) = 3.)
SVP
Joined: 16 Nov 2010
Posts: 1663
Location: United States (IN)
Concentration: Strategy, Technology
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

05 Apr 2011, 20:02
2t = 6(t-1)

=> t = 6/4 = 3/2 hrs

2* 2T = 6(T - 1)

=> 4T = 6T - 6

=> T = 3 hrs

So T - t = 3 - 3/2 = 3/2 hrs

Time in min = 90 min

_________________

Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

GMAT Club Premium Membership - big benefits and savings

Director
Joined: 01 Feb 2011
Posts: 755
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

17 Apr 2011, 17:41
6t = 2(t+1) => t = (1/2) hr
6t = 2* 2(t+1) => t =2 hrs
Positive difference = 2-(1/2)
=(3/2) hrs
= 90 minutes

Posted from my mobile device
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7450
Location: Pune, India
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

17 Apr 2011, 18:21
7
KUDOS
Expert's post
1
This post was
BOOKMARKED
Note that there are two different questions being discussed here:
One posted by neoreaves, the original poster - the answer to that is 108 mins;
the other posted by HelloKitty - the answer to that is 90 mins.

Both are based on the same logic but ask a different question.

Here I am discussing the logic and providing the answer to the question asked by HelloKitty.

HelloKitty wrote:
Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered?

A) 60
B) 72
C) 84
D) 90
E) 120

There is also a logical way to answer this without equations (you still may want to stick to equations in such questions during the exam but consider the logical solution an intellectual exercise)

Say Linda starts at 12:00. In an hour i.e. at 1:00, Linda has traveled 2 miles. Now Tom needs to cover the distance that Linda is covering now plus he has to cover the extra 2 miles to cover the same distance as Linda. Out of his speed of 6 mph, 2 mph is utilized in covering what Linda is covering right now (since Linda's speed is also 2 mph) and the rest 4 mph can be used to catch up the 2 miles. So it will take him half an hour (2miles/4mph) to cover as much distance as Linda has covered.

Now, at 1:30, they are both 3 miles away from point A. Now, Tom has to cover twice the distance that Linda covers from now on and he has to cover another 3 miles (to double Linda's current distance of 3 miles). From now on, 4mph of his 6 mph speed will go in covering twice of what Linda is covering at 2mph and the rest 2 mph of his 6 mph speed will go in covering the extra 3 miles that he has to cover. So it will take him 1.5 hours (3miles/2mph) to cover double of what Linda covers.

Since it took him 1.5 hrs (90 mins) extra after covering the same distance as Linda, this is the required time difference.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Senior Manager Joined: 08 Nov 2010 Posts: 408 WE 1: Business Development Re: Rates & Work: Walk Away [#permalink] ### Show Tags 19 Apr 2011, 05:56 7 This post received KUDOS 2 This post was BOOKMARKED i did it very simple similar to Karishma after 1 hour - L=2, T=0 after 1.5 - L=3, T=3 (first timing point) after 2 hours - L=4, T=6 after 2.5 hours - L=5, T=9 After 3 hours - L=6, T=12. DONE! 20 seconds! very safe way. _________________ Current Student Joined: 21 May 2012 Posts: 97 Location: United States (CA) Re: Tom and Linda stand at point A. [#permalink] ### Show Tags 31 May 2012, 13:29 E When Tom has covered 1/2 Linda's distance, the following equation will hold: 6T = 0.5(2(T + 1)). We can solve for T: 6T = 0.5(2(T + 1)) 6T = 0.5(2T + 2) 6T = T+1 5T = 1 T = 1/5 So it will take Tom 1/5 hour, or 12 minutes, to cover 1/2 Linda's distance. When Tom has covered twice Linda's distance, the following equation will hold: 6T = 2(2(T + 1)). We can solve for T: 6T = 2(2(T + 1)) 6T = 2(2T + 2) 6T = 4T + 4 2T = 4 T = 2 So it will take Tom 2 hours, or 120 minutes, to cover twice Linda's distance. We need to find the positive difference between these times: 120 – 12 = 108. Manager Joined: 12 May 2012 Posts: 83 Location: India Concentration: General Management, Operations GMAT 1: 650 Q51 V25 GMAT 2: 730 Q50 V38 GPA: 4 WE: General Management (Transportation) Re: Rates & Work: Walk Away [#permalink] ### Show Tags 01 Jun 2012, 03:14 VeritasPrepKarishma wrote: HelloKitty wrote: Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? A) 60 B) 72 C) 84 D) 90 E) 120 There is also a logical way to answer this without equations (you still may want to stick to equations in such questions during the exam but consider the logical solution an intellectual exercise) Say Linda starts at 12:00. In an hour i.e. at 1:00, Linda has traveled 2 miles. Now Tom needs to cover the distance that Linda is covering now plus he has to cover the extra 2 miles to cover the same distance as Linda. Out of his speed of 6 mph, 2 mph is utilized in covering what Linda is covering right now (since Linda's speed is also 2 mph) and the rest 4 mph can be used to catch up the 2 miles. So it will take him half an hour (2miles/4mph) to cover as much distance as Linda has covered. Now, at 1:30, they are both 3 miles away from point A. Now, Tom has to cover twice the distance that Linda covers from now on and he has to cover another 3 miles (to double Linda's current distance of 3 miles). From now on, 4mph of his 6 mph speed will go in covering twice of what Linda is covering at 2mph and the rest 2 mph of his 6 mph speed will go in covering the extra 3 miles that he has to cover. So it will take him 1.5 hours (3miles/2mph) to cover double of what Linda covers. Since it took him 1.5 hrs (90 mins) extra after covering the same distance as Linda, this is the required time difference. Logic always beats everything. It was beautifully explained. U made it very simple to understand. Intern Joined: 31 Oct 2011 Posts: 19 Schools: ESSEC '15 (A) GMAT 1: 650 Q45 V35 Re: Tom and Linda stand at point A. Linda begins to walk in a [#permalink] ### Show Tags 11 Sep 2012, 04:14 Really confusing!! Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? The answer is 90min Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? The answer is 108 min The answer depends on the question stem! Therefore the OA is not correct! Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7450 Location: Pune, India Re: Tom and Linda stand at point A. Linda begins to walk in a [#permalink] ### Show Tags 11 Sep 2012, 21:10 Maxswe wrote: Really confusing!! Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover the exact distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? The answer is 90min Tom and Linda stand at point A. Linda begins to walk in a straight line away from Tom at a constant rate of 2 miles per hour. One hour later, Tom begins to jog in a straight line in the exact opposite direction at a constant rate of 6 miles per hour. If both Tom and Linda travel indefinitely, what is the positive difference, in minutes, between the amount of time it takes Tom to cover half of the distance that Linda has covered and the amount of time it takes Tom to cover twice the distance that Linda has covered? The answer is 108 min The answer depends on the question stem! Therefore the OA is not correct! Yes, there are two different versions and hence the different answers. I have edited the OA. Hope it sorts out the confusion. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

Veritas Prep Reviews

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 16030
Re: Tom and Linda stand at point A. Linda begins to walk in a [#permalink]

### Show Tags

28 Nov 2013, 07:56
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Intern
Joined: 14 Oct 2013
Posts: 16
Location: India
Concentration: General Management
Re: Tom and Linda stand at point A. Linda begins to walk in a [#permalink]

### Show Tags

10 Jan 2014, 07:08
hi bunuel,

this question has been troubling for a while could you please provide an alternative method for this question?

Also, I have been been trying to use the concept of relative speed in the context of this question, ( both bodies moving in the opposite direction) but I dont seem to reach the answer with that... do you have a way to solve with the relative speeds ? or the only way to solve is the way its been mentioned?

Senior Manager
Joined: 28 Apr 2014
Posts: 282
Re: Rates & Work: Walk Away [#permalink]

### Show Tags

03 May 2014, 06:54
1
KUDOS
144144 wrote:
i did it very simple similar to Karishma

after 1 hour - L=2, T=0
after 1.5 - L=3, T=3 (first timing point)
after 2 hours - L=4, T=6
after 2.5 hours - L=5, T=9
After 3 hours - L=6, T=12. DONE!
20 seconds! very safe way.

Indeed quick but relying on the premise that answer will be coming out early in the table
MBA Blogger
Joined: 19 Apr 2014
Posts: 99
Location: India
Concentration: Strategy, Technology
WE: Analyst (Computer Software)
Re: Tom and Linda stand at point A. Linda begins to walk in a [#permalink]

### Show Tags

28 Aug 2014, 00:50
Cannot remember the above tricks for exam day. Need more solutions for this!!
_________________

Warm Regards.
Visit My Blog

Re: Tom and Linda stand at point A. Linda begins to walk in a   [#permalink] 28 Aug 2014, 00:50

Go to page    1   2    Next  [ 26 posts ]

Similar topics Replies Last post
Similar
Topics:
4 Tom and Linda stand at Point A. Linda begins to walk in a straight 5 16 Feb 2017, 01:00
1 In 10 years Linda will be as old as Bobby is now. Thirty years ago Bob 11 27 Jan 2017, 10:34
80 Alex and Brenda both stand at point X. Alex begins to walk a 40 31 May 2017, 04:25
22 Linda and Angela contract to paint a neighbor's house. Even 18 07 Feb 2017, 03:06
1 Linda and Angela contract 9 26 Sep 2011, 13:56
Display posts from previous: Sort by