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# (0.08)^-4/(0.04)^-3

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Intern
Joined: 16 Nov 2013
Posts: 28
Location: United States
Concentration: Entrepreneurship, General Management
GPA: 3.49

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20 Nov 2013, 22:38
1
3
00:00

Difficulty:

15% (low)

Question Stats:

79% (01:42) correct 21% (02:19) wrong based on 142 sessions

### HideShow timer Statistics

$$\frac{0.04^3}{0.08^4}$$

A) (-16/25)
B) (16/25)
C) (25/16)
D) 16
E) 25

Step by step please.
Manager
Joined: 27 Jul 2011
Posts: 53
Re: (.08)^-4 / (.04)^-3  [#permalink]

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20 Nov 2013, 23:07
1
This is how I approached:
[(0.04)^3]/[(0.08)^4]
= [(0.04)^3]/[(0.04 X 2)^4]
= [(0.04)^3]/[(0.04)^4 X 2^4]
=[1]/[(0.04)^1 X 2^4]
= [1]/[(0.04) X 16]
= 1/0.64
=1/(64/100)
=100/64
= 25/16 Answer C
VP
Joined: 02 Jul 2012
Posts: 1165
Location: India
Concentration: Strategy
GMAT 1: 740 Q49 V42
GPA: 3.8
WE: Engineering (Energy and Utilities)

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21 Nov 2013, 02:55
3
1
$$(\frac{4}{100})^3/(\frac{8}{100})^4$$

$$(\frac{4}{100})^3*(\frac{100}{8})^4$$

$$(\frac{4^3}{100^3})*(\frac{100^4}{8^4})$$

$$(\frac{4^3}{8^4})*100$$

$$(\frac{64}{8^4})*100$$

$$(\frac{1}{64})*100$$

$$\frac{25}{16}$$

registerincog wrote:
$$\frac{0.04^3}{0.08^4}$$

A) (-16/25)
B) (16/25)
C) (25/16)
D) 16
E) 25

Step by step please.

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13 Apr 2018, 13:41
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: (0.08)^-4/(0.04)^-3   [#permalink] 13 Apr 2018, 13:41
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# (0.08)^-4/(0.04)^-3

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