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In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w

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In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w [#permalink]

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New post 27 Sep 2017, 11:36
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In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, what is the area of triangle BDE?

A. 9
B. 12
C. 15
D. 16
E. 18

Source : Experts Global
[Reveal] Spoiler: OA

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Director
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Kudos [?]: 338 [0], given: 591

In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w [#permalink]

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New post 27 Sep 2017, 15:15
pushpitkc wrote:
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In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, what is the area of triangle BDE?

A. 9
B. 12
C. 15
D. 16
E. 18

Source : Experts Global

Area of triangle BDE = \(\frac{b*h}{2}\)

Base = DE = 5
Height = 6

Height of triangle = height of rectangle
AD = BC = 6

Area of triangle BDE = \(\frac{5*6}{2}=15\)

ANSWER C

Hmm. Is the rectangle's length useless information? Or are we not to assume the triangle's height = height of rectangle?
Not sure why not.

If not, calculate the area of the rectangle and subtract areas of the other two triangles:

Area of rectangle ABCD: (6 * 8) = 48

Area of triangle ABD: \(\frac{6*8}{2}\) = 24

Area of triangle BCE:
base = CE = 3 because
CE = (AB - DE) = (8 - 5) = 3
height = BC = AD = 6
Area of BCE: \(\frac{3*6}{2}\) = 9

Rectangle area - Area of two triangles = Area of triangle BDE

48 - 24 - 9 = 15

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Re: In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w [#permalink]

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New post 29 Sep 2017, 08:06
Easier way is that AD=6, DE =5, so according to triangle area formula, ab/2, 6*5/2=15; C

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Re: In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w   [#permalink] 29 Sep 2017, 08:06
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In the figure shown, ABCD is a rectangle. If AD = 6, AB = 8, DE = 5, w

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