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Total amount collected from an officer for a charity cause was $250.

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Director
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Total amount collected from an officer for a charity cause was $250.  [#permalink]

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Total amount collected from an officer for a charity cause was $250. If each employee contributed either $20 or $25, how many employees contributed $20?

I. The number of employees in the office is 11.
II. The number of employees who gave $25 was 1 more than the number of employees who gave $20.
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Re: Total amount collected from an officer for a charity cause was $250.  [#permalink]

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New post 01 Mar 2019, 10:53
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kiran120680 wrote:
Total amount collected from an officer for a charity cause was $250. If each employee contributed either $20 or $25, how many employees contributed $20?

I. The number of employees in the office is 11.
II. The number of employees who gave $25 was 1 more than the number of employees who gave $20.


IF YOU FIND MY EXPLANATION HELPFUL, PLEASE GIVE ME KUDOS

Ok, this is an algebraic translation word problem. For DS questions of this time, it is helpful to know that in general if we have n equations for n variables, we have enough information to find the variables.

The information form the question allows us to write a linear equation. Let x be the number of employees who contributed $25 and y be the number of employees who contributed $20 Then 25x + 20y =250. We need 1 more equation to state sufficiency.

(1) The number of employees in the office is 11. We can then write x + y =11. We now have 2 equations with 2 variables, so we can mark sufficient

(2) The number of employees who gave $25 was 1 more than the number of employees who gave $20. WE can then write x=y+1. We now have 2 variables with 2 equations, so we can mark sufficient

Answer is D
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Re: Total amount collected from an officer for a charity cause was $250.   [#permalink] 01 Mar 2019, 10:53
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Total amount collected from an officer for a charity cause was $250.

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