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Traingles

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Manager
Joined: 30 Sep 2009
Posts: 120

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28 Sep 2011, 14:37
00:00

Difficulty:

(N/A)

Question Stats:

25% (00:00) correct 75% (01:03) wrong based on 4 sessions

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if two sides of the triangle are 12 and 8,then which of the following could be the area of the traingle

I 35
II 48
III 56

A. I only
B I and II
c .I and III
d. II and III
e I II and III

Guys need the explanation also.....
Senior Manager
Joined: 28 Jun 2009
Posts: 444
Location: United States (MA)

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28 Sep 2011, 15:19
Are you sure its "Area" they are asking for and not "Perimeter"?
Current Student
Joined: 21 Aug 2010
Posts: 205

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29 Sep 2011, 00:17
I also feel the same that it should be perimeter and not area.

But I also feel that this post should have been posted in the Quants section and not in the GMAT Experience section

BR
Mandeep
Manager
Status: Still Struggling
Joined: 03 Nov 2010
Posts: 137
Location: India
GMAT Date: 10-15-2011
GPA: 3.71
WE: Information Technology (Computer Software)

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29 Sep 2011, 03:48
IMO, I and II only..
Wats the OA?
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Manager
Joined: 30 Sep 2009
Posts: 120

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29 Sep 2011, 07:10
ya the question is for area and not the perimeter.....

Sorry for posting in the wrong section..
Intern
Joined: 01 Mar 2006
Posts: 23

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29 Sep 2011, 07:28
Ans : B
i and ii only.
the max area can be 48 or less. So it is 35 or 48
Current Student
Joined: 21 Aug 2010
Posts: 205

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29 Sep 2011, 10:04
I also feel that it should be I and II.
What's the OA??
Intern
Joined: 24 Sep 2011
Posts: 9

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29 Sep 2011, 17:14
1
KUDOS
Area is fine.

Max area is 12*8/2 = 248. so anything equal or under 48 can be the area.
Director
Joined: 01 Feb 2011
Posts: 755

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29 Sep 2011, 18:29
1
KUDOS
area of the triangle with two known side lengths a , b = (1/2)(a*b)*sin(a,b)

(a,b) is the angle between sides a and b

area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)

sin(a,b) is always between 0 and 1 inclusive. (as thats the sin range)

=> area = 48*[0,..1]

=>0<=area <=48

I and II are only possible options that satisfy the above condition.

Intern
Joined: 09 Sep 2011
Posts: 15
Location: United States

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30 Sep 2011, 14:42

how you come up with max area of 48.

thanks .
Director
Joined: 01 Feb 2011
Posts: 755

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30 Sep 2011, 18:55
area = (1/2)*8*12*sin(a,b) = 48 sin(a,b)

maximum value of sin angle is 1. so maximum value of area in the above statement = 48*1= 48

yourpal wrote:

how you come up with max area of 48.

thanks .
Manager
Joined: 20 Nov 2010
Posts: 218

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01 Oct 2011, 02:04
Agreed the max area is 1/2 * 12 * 8 * sin@ and max value of sin@ is 1 = 48
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~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
MGMAT 6 650 (51,31) on 31/8/11
MGMAT 1 670 (48,33) on 04/9/11
MGMAT 2 670 (47,34) on 07/9/11
MGMAT 3 680 (47,35) on 18/9/11
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CR notes
http://gmatclub.com/forum/massive-collection-of-verbal-questions-sc-rc-and-cr-106195.html#p832142
http://gmatclub.com/forum/1001-ds-questions-file-106193.html#p832133
http://gmatclub.com/forum/gmat-prep-critical-reasoning-collection-106783.html
http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html
http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html?hilit=chineseburned

Re: Traingles   [#permalink] 01 Oct 2011, 02:04
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