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#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t

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Math Expert V
Joined: 02 Sep 2009
Posts: 59588
Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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Difficulty:   15% (low)

Question Stats: 74% (01:34) correct 26% (02:23) wrong based on 32 sessions

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Competition Mode Question

Triangle ABC has sides $$Z$$, $$√Z$$ and $$Z^2$$, where $$Z$$ is an integer. What is the area of ABC?

A. $$√2$$

B. $$2$$

C. $$2√2$$

D. $$\frac{√3}{4}$$

E. $$\frac{√15}{2}$$

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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1
Let Z=1
If a side Z=1, then √Z=1 and Z^2=1....which is nothing but equilateral triangle.

Area of equilateral triangle ABC= √3/4 * side^2 = √3/4 * 1^2 = √3/4

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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Ah an Excellent question.

The catch here is that, for no values of Z except 1,a triangle is possible.

Lets take the case of Z=2, the sides will be 2 , root2 and 4. Now third side is longer than the sum of other two sides, which is not possible.

Hence Z=1. Triangle is equilateral. And area is root3/4.

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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Let Z,1
p=1+1+1=3
According to Heron's formula, we have
P=√p/2*(p/2-1)*(p/2-1)*(p/2-1)=
√3/2*1/2*1/2*1/2=√3/16= √3 /4
Option D

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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Z=1
So triangle will be equilateral

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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Since Z is an integer only one positive value(length can’t be negative) is possible. Thus, $$Z = 1$$ and $$√Z = 1$$ and $$Z^2 = 1$$ as $$Z = 2$$ would not make a triangle because other two side would be $$√Z = √2$$ and $$Z^2 = 4$$. Here $$Z + √Z < Z^2$$ where sum of two smaller sides must be greater than the largest side.

Hence the triangle has each side equal to 1. So, it’s an equilateral triangle.

Therefore Area of equilateral triangle $$= \frac{√3}{4} * side^2$$.
 $$= \frac{√3}{4}$$

Also, using Hero’s formula
$$S = \frac{(a + b + c)}{2}$$ where a, b and c are three sides of triangle.
$$S = \frac{3}{2}$$

Area of triangle $$= √(s(s-a)(s-b)(s-c))$$
 $$= √(\frac{3}{2} * (\frac{3}{2}-1) * (\frac{3}{2}-1) * (\frac{3}{2}-1))$$
 $$= √(\frac{3}{2} * (\frac{1}{2})^3)$$
 $$= \frac{√3}{4}$$

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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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if we check the sum of sides property

z+z^2 > sqrt(z) for many values
also sqrt(z)+z^2 >z for many values
but z+sqrt(z)>z^2 only if z=1

so area is (sqrt(3)*z)/4 ...... OA: D
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Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t  [#permalink]

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According to given sides triangle ABC is possible only when all sides are equal I.e when z=√z=z^2, it happens when z=1 , for any other integer third side rule does not satisfy, so since all sides are equal area of equilateral triangle is√3/4 a^2 = √3/4

Posted from my mobile device Re: Triangle ABC has sides Z, √Z and Z^2, where Z is an integer. What is t   [#permalink] 19 Sep 2019, 06:19
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