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# Triangles

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Manager
Joined: 01 Jun 2006
Posts: 77

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12 Dec 2006, 04:36
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Manager
Joined: 10 Jul 2006
Posts: 72

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12 Dec 2006, 07:58
C for me. I use the formula that the ratio of area between the 2 similar shapes = (ratio of the side)^2. That means Area of big ABC / Area of small ABC = (S/s)^2 = 2

So, S/s = sqrt 2. S = s (sqrt2) ans C
Intern
Joined: 24 Feb 2006
Posts: 48

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12 Dec 2006, 08:34
for similar triangles
h/s = H/S where h = height of small triangle and H for other one.
=>h=Hs/S

given,
Area of bigger triangle = 2 * Area of small triangle
=> 1/2*S*H = 2 * 1/2* s*h
=> 1/2*S*H = s*Hs/S
=> S^2 = 2s
=> S = sqrt(2) s

Ans C.
Manager
Joined: 01 Jun 2006
Posts: 77

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12 Dec 2006, 10:51
Intern
Joined: 24 Feb 2006
Posts: 48

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12 Dec 2006, 15:01
Posted: Tue Dec 12, 2006 9:34 am Post subject:

--------------------------------------------------------------------------------

for similar triangles
h/s = H/S where h = height of small triangle and H for other one.
=>h=Hs/S

given,
Area of bigger triangle = 2 * Area of small triangle
=> 1/2*S*H = 2 * 1/2* s*h
=> 1/2*S*H = s*Hs/S
=> S^2 = 2s^2 (has typo before)
=> S = sqrt(2) s
12 Dec 2006, 15:01
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