It is currently 12 Dec 2017, 16:00

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Tricky question

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Manager
Manager
User avatar
Status: Back to (GMAT) Times Square!!!
Joined: 15 Aug 2011
Posts: 178

Kudos [?]: 88 [0], given: 25

Location: United States (IL)
GMAT 1: 650 Q49 V30
WE: Information Technology (Computer Software)
Reviews Badge
Tricky question [#permalink]

Show Tags

New post 23 Nov 2011, 05:28
Just wanted to know whether there is a short-cut way of solving this question? Can anyone please help me with this?

Attachment:
11.jpg
11.jpg [ 61.05 KiB | Viewed 1289 times ]


Thanks,
V.

Kudos [?]: 88 [0], given: 25

Intern
Intern
User avatar
Joined: 20 Aug 2010
Posts: 37

Kudos [?]: 35 [0], given: 0

Re: Tricky question [#permalink]

Show Tags

New post 23 Nov 2011, 22:45
The area of the figure inside the circle seems to be composed of the half of the circle (because the cords form a right angle and therefore the hypotenuse of the triangle is the diameter of the circle cutting the middle of the circle) + the right triangle in the bottom left of the square. We should find its area.
Area of 1/2 circle = PiR^2/2 = Pi/2 (as radius is 2/2=1)
Area of triangle is 1/2 * 2 (hypotenuse) * 1 (hight to hypotenuse, which is a radius =1) =1
diff = Area of the Square - area of our figure = 2*2 - Pi/2 - 1
Ratio = diff / area of the square

Kudos [?]: 35 [0], given: 0

Intern
Intern
avatar
Joined: 31 Jul 2011
Posts: 13

Kudos [?]: 4 [0], given: 7

Re: Tricky question [#permalink]

Show Tags

New post 24 Nov 2011, 00:42
A . Followed the similar approach as Postal

Kudos [?]: 4 [0], given: 7

Re: Tricky question   [#permalink] 24 Nov 2011, 00:42
Display posts from previous: Sort by

Tricky question

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.