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# TRY this one_PS_Percent_exceeding speed

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Director
Joined: 22 Aug 2007
Posts: 566

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03 Sep 2007, 23:08
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will provide with answer later, plz explain

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Manager
Joined: 03 Sep 2006
Posts: 233

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03 Sep 2007, 23:46

Total = 100, some exceed, some - do not
From exceeding:
10 = exceeded + ticketed
20 = exceeded + not ticketed

This is my logic.

P.S> Sound like my favorite CR =)
Director
Joined: 03 May 2007
Posts: 872
Schools: University of Chicago, Wharton School
Re: TRY this one_PS_Percent_exceeding speed [#permalink]

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04 Sep 2007, 00:23
IrinaOK wrote:
will provide with answer later, plz explain

its very confusing.

= 10%/(100-20)%

= 12.5%
Director
Joined: 22 Aug 2007
Posts: 566
Re: TRY this one_PS_Percent_exceeding speed [#permalink]

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04 Sep 2007, 00:37
Fistail wrote:
IrinaOK wrote:
will provide with answer later, plz explain

its very confusing.

= 10%/(100-20)%

= 12.5%

nothing is more confusing than answer without explanation............
:=(

no answer would be worse, though...
Director
Joined: 22 Aug 2007
Posts: 566
Re: TRY this one_PS_Percent_exceeding speed [#permalink]

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04 Sep 2007, 00:50
IrinaOK wrote:
will provide with answer later, plz explain

here, I got it,

lets say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0,1N=0,8X
X=0,1/0,8=0,125 or 12,5 percent

0,8=1-0,2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!
GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5043
Location: Singapore

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04 Sep 2007, 01:05
Here's how you solve it.
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table.jpg [ 45.66 KiB | Viewed 550 times ]

Director
Joined: 03 May 2007
Posts: 872
Schools: University of Chicago, Wharton School
Re: TRY this one_PS_Percent_exceeding speed [#permalink]

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04 Sep 2007, 08:08
there you go.

IrinaOK wrote:
IrinaOK wrote:
will provide with answer later, plz explain

here, I got it,

lets say
N-total number of motorists
X-total number of those who exceed the speed limit
then,
0.1N=0.8X
X=0.1/0.8=0.125 or 12.5 percent

0.8=1-0.2

Point here is to stay clear about total number of motorists and those who exceed...

Thank you, Fistail!
Re: TRY this one_PS_Percent_exceeding speed   [#permalink] 04 Sep 2007, 08:08
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