Bunuel wrote:
Twelve engineers can complete a task in 7 Hours. Twelve engineers started the task at 10 am but starting from 1 pm, one engineer leaves every hour. At what time the task gets completed?
A. 5.30 pm
B. 6.00 pm
C. 6.30 pm
D. 7.00 pm
E. 7.30 pm
Are You Up For the Challenge: 700 Level QuestionsSince the rate for 12 engineers is 1/7, after 3 hours of work (from 10 am to 1 am), 3 x 1/7 = 3/7 of the job had been completed and therefore 4/7 of the job is left to be completed.
Furthermore, the rate of 1 engineer is (1/7)/12 = 1/84, so the rate of 11 engineers is 11/84.
So, by 2 pm, 4/7 - 11/84 = 48/84 - 11/84 = 37/84 of the job is left to be completed.
The rate for 10 engineers is 10/84.
So, by 3 pm, 37/84 - 10/84 = 27/84 of the job is left to be completed.
The rate for 9 engineers is 9/84.
So, by 4 pm, 27/84 - 9/84 = 18/84 of the job is left to be completed
The rate for 8 engineers is 8/84.
So, by 5 pm, 18/84 - 8/84 = 10/84 of the job is left to be completed.
The rate for 7 engineers is 7/84.
So, by 6 pm, 10/84 - 7/84 = 3/84 of the job is left to be completed.
The rate of 6 engineers is 6/84.
So, by 6:30 pm, 3/84 - 1/2 x 6/84 = 0 of the job is left to be completed. That is, the job will be completed by 6:30 pm.
Alternate Solution:
Since it takes 12 engineers 7 hours to do the job, the total job can be accomplished in 84 hours.
From 10 - 1, we have 12 x 3 = 36 hours of work accomplished.
From 1 - 2, we have 11 additional hours, for a total of 36 + 11 = 47 hours.
From 2 - 3, we have 10 additional hours, for a total of 47 + 10 = 57 hours.
From 3 - 4, we have 9 additional hours, for a total of 57 + 9 = 66 hours.
From 4 - 5, we have 8 additional hours, for a total of 66 + 8 = 74 hours.
From 5 - 6, we have 7 additional hours, for a total of 74 + 7 = 81 hours.
Since the entire job requires 84 hours, we need only 3 more hours of work, which can be accomplished by the 6 remaining engineers in half an hour. Thus, the job will be completed at 6:30 pm.
Answer: C