Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 25 May 2017, 16:12

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Two different numbers when divided by the same divisor left

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Intern
Joined: 05 May 2003
Posts: 22
Followers: 0

Kudos [?]: 0 [0], given: 0

Two different numbers when divided by the same divisor left [#permalink]

### Show Tags

17 May 2003, 08:30
00:00

Difficulty:

(N/A)

Question Stats:

100% (02:21) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Two different numbers when divided by the same divisor left a
remainder of 11 and 21 respectively and when the sum of the numbers
was divided the remainder was 4. what is the divisor??
a) 36
b) 28
c) 14
d) 9
SVP
Joined: 03 Feb 2003
Posts: 1604
Followers: 9

Kudos [?]: 268 [0], given: 0

### Show Tags

18 May 2003, 05:10
Given that:

R=kX+11
Q=mX+21
R+Q=nX+4
**************************************
Add P+Q=(k+m)X+32, which is equal to nX+4

32-4=28
Intern
Joined: 05 May 2003
Posts: 1
Followers: 0

Kudos [?]: 0 [0], given: 0

### Show Tags

20 May 2003, 07:53
just an extenion to your solution...
it could be either of 28 or 14 but since the remainder of 21 implied the divisor should be larger than 21 the anwer is 28
Senior Manager
Joined: 19 May 2004
Posts: 291
Followers: 1

Kudos [?]: 15 [0], given: 0

### Show Tags

30 Jun 2004, 11:01
Can someone please explain the solution to this problem ?
Senior Manager
Joined: 21 Mar 2004
Posts: 444
Location: Cary,NC
Followers: 3

Kudos [?]: 72 [0], given: 0

### Show Tags

30 Jun 2004, 12:49
Hi Dookie,

let the first no be x.

x/n = (an integer) + 11 = u + 11 - equation 1

similarly

y/n = (an integer) + 21 = v + 21 - equation 2

(x+y)/n = (an integer) + 4 = w + 4 - equation 3

eq1+eq2 = eq3 - equation 4

simplifies
n(u+v) + 32 = nw + 4 - here u,v,w are integers.

this means that n is a factor of 28.........bcoz n<=32-4 or n<=28

the factors of 28 are 14,7 etc.

since we have seen a remainder of 21 this means that n>21 , therefore n=28.

- ash
_________________

ash
________________________
I'm crossing the bridge.........

Manager
Joined: 08 Jun 2004
Posts: 245
Location: INDIA
Followers: 2

Kudos [?]: 9 [0], given: 0

### Show Tags

30 Jun 2004, 13:09
I substituted the numbers and got the ans as 28...

the easiest way with substitution...take a number that s more than 21 cos the least number that can divide 21 perfect =21 ...

take /37/28= reminder 11 and add 10 to this reminder and that wud get U 47 which gives a reminder of 21...

add both 37+47 = 88
now 88/28 leaves a reminder 4...

hope that helps!

Have fun
_________________

the whole worldmakes way for the man who knows wer he's going... good luck

30 Jun 2004, 13:09
Display posts from previous: Sort by

# Two different numbers when divided by the same divisor left

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.