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Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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06 Sep 2013, 03:29
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Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? A) 90 B) 130 C) 150 D) 320 E) 450
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Last edited by Bunuel on 06 Sep 2013, 03:37, edited 1 time in total.
Renamed the topic and edited the question.



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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06 Sep 2013, 03:38
caro2789 wrote: Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?
A) 90 B) 130 C) 150 D) 320 E) 450 In one hour A covers 90 kilometers. So, by the time B starts traveling the distance between the trucks is 77090=680 kilometers. To cover that distance the trucks need (total distance)/(combined rate)=680/(90+80)=4 hours. In 4 hours B covered 4*80=320 kilometers and A covered 770320=450 kilometers. The difference = 450  320 = 130 kilometers. Answer: B. P.S. Please read carefully and follow: rulesforpostingpleasereadthisbeforeposting133935.html Please pay attention to the rule #3. Thank you.
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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06 Sep 2013, 04:07
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aDistance traveled by A bDistance traveled by B
a+b=770 need to find ab=?
Equating Time taken to meet \(\frac{a}{90} = 1+\frac{b}{80}\)
Solve with b=770a in above a=450, so b=770450=320 ab=450320=130



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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06 Sep 2013, 18:19
caro2789 wrote: Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?
A) 90 B) 130 C) 150 D) 320 E) 450 1. Driver A traveled totally for 1 hr + (77090)/ (90+80) hrs= 5 hrs. Distance traveled = 90*5=450 km 2. Driver B traveled 1 hr less i.e., he traveled for 4 hrs. Distance traveled = 80*4=320 km 3. Difference is, 450320=130km
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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09 Sep 2013, 03:46
Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?
We are looking for how long it takes the two drivers to meet at some point between both ends of the highway. We are NOT looking for how long it takes for each truck to reach the other side of the highway. If Driver B sets off one hour after A, then A has already traveled for 90km when driver B begins to move. After one hour, driver A and B have to cover 77090 = 680 km. Their total average speed is 90+80 km/h which means it will take them 680km/170km/h = 4 hours. In this time A travels 90 + (4*90) = 450 km which means that B travels 770  450 = 320 km so A travels 130 km more than B.
ANSWER: B) 130
I got tripped up when I couldn't figure out how to determine how long B traveled for. I was trying to solve for how long it would take B to travel from one side of the highway to the other when the question was asking for how long it would take for them too pass one another. All this means is that A travels for one more hour than B and that from that distance (77090 = 680km) we can determine how long it took for them to meet up. When we calculate how many km A traveled, we multiply the time it took A to meet B by its rate and add in the 90 km it traveled before B set off.



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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27 Feb 2014, 18:45
Bunuel wrote: caro2789 wrote: Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?..
A) 90 B) 130 C) 150 D) 320 E) 450 In one hour A covers 90 kilometers. So, by the time B starts traveling the distance between the trucks is 77090=680 kilometers. To cover that distance the trucks need (total distance)/(combined rate)=680/(90+80)=4 hours. In 4 hours B covered 4*80=320 kilometers and A covered 770320=450 kilometers. The difference = 450  320 = 130 kilometers. Answer: B. P.S. Please read carefully and follow: rulesforpostingpleasereadthisbeforeposting133935.html Please pay attention to the rule #3. Thank you. Hi Bunuel Please let me understand the red line sentence..... Rgds Prasannajeet



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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28 Feb 2014, 01:37
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Difference between Distance travelled by A & Distance travelled by B when they crossed each other
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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03 May 2014, 01:59
Bunuel wrote: caro2789 wrote: Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?
A) 90 B) 130 C) 150 D) 320 E) 450 ]In one hour A covers 90 kilometers. So, by the time B starts traveling the distance between the trucks is 77090=680 kilometers. To cover that distance the trucks need (total distance)/(combined rate)=680/(90+80)=4 hours. In 4 hours B covered 4*80=320 kilometers and A covered 770320=450 kilometers.The difference = 450  320 = 130 kilometers. Answer: B. Bunuel bit confused on the line highlighted above. If we take it conversly , In 4 hrs A covered 90*4 = 360 km , B would have covered 770360 = 410 kms. Am I missing something ? Is the rationale behind your sequencing of taking B first and subtracting for A is the fact that A has a higher speed so it would cover a larger distance ? My thought process was  For 1 hr only A was driving @ 90kph so distance covered = 90kph Thus remaining distance = 77090 = 680kph when both A and B are approaching each other. Now since time of start is same , distance covered is in ratio of speeds. Let distance covered by A = x , then B = 680x x/680x = 90/80. Solving for x , x= 360 = Distance A drove , 680x = 320 kph. Total extra dist travelled by A = 360 + 90 ( of first 1 hr)  320 = 130 kph



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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03 May 2014, 04:30
himanshujovi wrote: Bunuel wrote: caro2789 wrote: Two heavily loaded sixteenwheeler transport trucks are 770 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway?
A) 90 B) 130 C) 150 D) 320 E) 450 ]In one hour A covers 90 kilometers. So, by the time B starts traveling the distance between the trucks is 77090=680 kilometers. To cover that distance the trucks need (total distance)/(combined rate)=680/(90+80)=4 hours. In 4 hours B covered 4*80=320 kilometers and A covered 770320=450 kilometers.The difference = 450  320 = 130 kilometers. Answer: B. Bunuel bit confused on the line highlighted above. If we take it conversly , In 4 hrs A covered 90*4 = 360 km , B would have covered 770360 = 410 kms. Am I missing something ? Is the rationale behind your sequencing of taking B first and subtracting for A is the fact that A has a higher speed so it would cover a larger distance ? My thought process was  For 1 hr only A was driving @ 90kph so distance covered = 90kph Thus remaining distance = 77090 = 680kph when both A and B are approaching each other. Now since time of start is same , distance covered is in ratio of speeds. Let distance covered by A = x , then B = 680x x/680x = 90/80. Solving for x , x= 360 = Distance A drove , 680x = 320 kph. Total extra dist travelled by A = 360 + 90 ( of first 1 hr)  320 = 130 kph A starts driving 1 hour before B. They meet 4 hours AFTER B starts. If you want to do the other way around it would be: A travels for 4+1=5 hours, thus covers 5*90=450 kilometers, hence B covers 770450=320 kilometers. The difference = 450320 = 130 kilometers. Hope it's clear.
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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03 May 2014, 07:32
Hi Bunuel, first of all thank you for all the material you are posting. It is of great help and value! There is something I don't understand in this question, how come you can add their average speed? What is the reasoning behind that because in the document GMAT club math book, p. 39 it is written that you cannot add the speeds.. Thank you very much



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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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04 May 2014, 08:21
StephOD wrote: Hi Bunuel, first of all thank you for all the material you are posting. It is of great help and value! There is something I don't understand in this question, how come you can add their average speed? What is the reasoning behind that because in the document GMAT club math book, p. 39 it is written that you cannot add the speeds.. Thank you very much We CAN add or subtract rates (speeds) to get relative rate. For example if two cars are moving toward each other from A to B (AB=100 miles) with 10mph and 15mph respectively, then their relative (combined) rate is 10+15=25mph, and they'll meet in (time)=(distance)/(rate)=100/25=4 hours; Similarly if car x is 100 miles ahead of car y and they are moving in the same direction with 10mph and 15mph respectively then their relative rate is 1510=5mph, and y will catch up x in 100/5=20 hours. Hope it's clear.
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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29 May 2015, 02:50
Visualizing the problem in Distance and Speed question always helps in easy understanding of the question asked. Refer the below diagram We are given that the initial distance between drivers A and B is 770 kms. Driver A drives for an hour towards driver B before he starts driving Distance covered by driver A before driver B starts driving = Speed * time = 90 * 1 = 90 Kms So, when driver B starts driving , the distance between driver A and driver B is 770  90 = 680 kms. The problem can now be simplified to both drivers driving towards each other with constant speeds. Let's assume the time taken by them to meet is t. Speed of driver A = 90 kms/hour Speed of driver B = 80 kms/hour Let's assume the distance traveled by driver A is \(x\). Hence distance traveled by driver B = 680  \(x\) As the time taken by both of them to meet each other is same, we can write \(\frac{x}{90} = \frac{680x}{80}\) which gives us the value of \(x\) = 360 kms So total distance traveled by driver A = \(x\) + Initial distance covered by driver A before driver B starts driving = 360 + 90 = 450 kms Distance traveled by driver B = 680  \(x\) = 320 kms Hence, extra distance traveled by driver A = 450  320 = 130 kms
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Re: Two heavily loaded sixteenwheeler transport trucks are 770 [#permalink]
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23 Jul 2015, 14:02
I've been reading the website for a while and I'm always keen to see different approaches so I would like to share one that works for me:
Short version:
Truck A travels for an hour.
Distance remaining = 77090 = 680k
Ratio of speeds 9:8 > 680/17 = 40
Truck A = 90 + 40*9 = 450 Truck B = 40*8 = 320
Delta = 130km
Answer B
Long version:
1. Driver A drives for 1 hour at 90kph, this means that remaining distance to be traveled by both trucks is 680k (77090 )
2. Given the speeds you know that Truck A travels 9km for every 8km Truck B travels so a ratio of 9:8
3. Question is then whether 680 is divisible by 9+8 = 17 so that you can attribute each his slice of the drive?
4. Quick look at multiples of 17= 17, 34, 51, 68 and there it is. So you know that 680/17=40
5. Truck A has 9 slices of 40 = 360km and Truck B has 8 = 320km. Delta between the two is 40
6. BUT Truck A drove for an hour before Truck, so add 90. Answer is 130km
Answer is B  I'm not a whizz but I solved it in less than 80 seconds this way.
I'm a big fan of using the numbers and ratios like Karishma does in her explanations
I hope this is useful!




Re: Two heavily loaded sixteenwheeler transport trucks are 770
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