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Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and

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Re: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and [#permalink]

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New post 01 May 2017, 19:10
Bunuel wrote:
ishanbhat455 wrote:
Hi Bunuel,

I am not quite familiar with the allegation formula amit2k9 has used to solve this problem. Could you please show a simpler way of solving this problem?

Thanks,
Ishan


Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and they are sold fetching the profit 10% and 20% respectively. If the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4/3 and 5/3 times respectively, then the mixture will fetch the profit of
A. 18%
B. 20%
C. 21%
D. 23%
E. Cannot be determined

The profit on the first kind of vodka = x%;
The profit on the second kind of vodka = y%.

When they are mixed in the ratio 1:2 (total of 3 parts) the average profit is 10%: (x + 2y)/3 = 10.
When they are mixed in the ratio 2:1 (total of 3 parts) the average profit is 20%: (2x + y)/3 = 20.

Solving gives: x = 30% and y = 0%.

After the individual profit percent on them are increased by 4/3 and 5/3 times respectively the profit becomes 40% and 0%, on the first and te second kinds of vodka, respectively.

If they are mixed in equal ratio (1:1), then the mixture will fetch the profit of (40 + 0)/2 = 20%.

Answer: B.

Hope it's clear.


Hi Bunuel,

I think the question's wording should be changed from profit increased [b]by[/b] to profit increased to. Increased by would imply that the new profit is (1+4/3)x %
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Re: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and [#permalink]

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New post 04 Jun 2018, 06:37
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Re: Two kinds of Vodka are mixed in the ratio 1:2 and 2:1 and   [#permalink] 04 Jun 2018, 06:37

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