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Re: Two parking lots can hold a total of 115 cars. The Green lot can hold [#permalink]
Bunuel wrote:
Two parking lots can hold a total of 115 cars. The Green lot can hold 35 fewer cars than the Red lot. How many cars can the Red lot hold?

A. 35
B. 40
C. 50
D. 75
E. 85



Red lot = x

Green lot = x - 35.

x + x - 35 = 115

2x = 150

x = 75.

D is the correct answer.
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Re: Two parking lots can hold a total of 115 cars. The Green lot can hold [#permalink]
Bunuel wrote:
Two parking lots can hold a total of 115 cars. The Green lot can hold 35 fewer cars than the Red lot. How many cars can the Red lot hold?

A. 35
B. 40
C. 50
D. 75
E. 85


Let the number of cars in red lot = n

Green lot can hold 35 fewer cars than the Red lot
--> Number of cars in green lot = n - 35

Given, n + (n - 35) = 115
--> 2n - 35 = 115
--> 2n = 150
--> n = 75

Number of cars in red lot hold = n = 75

IMO Option D

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Re: Two parking lots can hold a total of 115 cars. The Green lot can hold [#permalink]
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Bunuel wrote:
Two parking lots can hold a total of 115 cars. The Green lot can hold 35 fewer cars than the Red lot. How many cars can the Red lot hold?

A. 35
B. 40
C. 50
D. 75
E. 85



We can let n = the number of cars the Red lot can hold and create the equation:

n + n - 35 = 115

2n = 150

n = 75

Answer: D
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Re: Two parking lots can hold a total of 115 cars. The Green lot can hold [#permalink]
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Re: Two parking lots can hold a total of 115 cars. The Green lot can hold [#permalink]
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