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• $450 Tuition Credit & Official CAT Packs FREE February 15, 2019 February 15, 2019 10:00 PM EST 11:00 PM PST EMPOWERgmat is giving away the complete Official GMAT Exam Pack collection worth$100 with the 3 Month Pack ($299) • Free GMAT practice February 15, 2019 February 15, 2019 10:00 PM EST 11:00 PM PST Instead of wasting 3 months solving 5,000+ random GMAT questions, focus on just the 1,500 you need. Two plots, one square and the other, circular, were equal in areas.  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Hide Tags Manager Joined: 25 Dec 2018 Posts: 146 Location: India GMAT 1: 490 Q47 V13 GPA: 2.86 Two plots, one square and the other, circular, were equal in areas. [#permalink] Show Tags 24 Jan 2019, 08:32 2 00:00 Difficulty: 45% (medium) Question Stats: 60% (02:12) correct 40% (02:31) wrong based on 17 sessions HideShow timer Statistics Two plots, one square and the other, circular, were equal in areas. If the cost of fencing the square plot and the circular plot were$ 2 per feet and $3 per feet respectively, what was the ration of the cost of fencing the square plot to that of the circular plot? A. Sq root π : 1 B. 4 sq root π : 3 C. 4 : sq root π D. 3 sq root π : 4 E. 4 : 3 sq root π Manager Status: Manager Joined: 27 Oct 2018 Posts: 155 Location: Malaysia Concentration: Strategy, International Business GPA: 3.67 WE: Pharmaceuticals (Health Care) Re: Two plots, one square and the other, circular, were equal in areas. [#permalink] Show Tags 24 Jan 2019, 11:31 2 akurathi12 wrote: Two plots, one square and the other, circular, were equal in areas. If the cost of fencing the square plot and the circular plot were$ 2 per feet and \$ 3 per feet respectively, what was the ration of the cost of fencing the square plot to that of the circular plot?

A. Sq root π : 1
B. 4 sq root π : 3
C. 4 : sq root π
D. 3 sq root π : 4
E. 4 : 3 sq root π

for square side 'd' and circle radius 'r'
$$d^2 = π r^2$$
$$d= r\sqrt{π}$$

cost of fencing the square S = $$4d*2$$
cost of fencing the circle C = $$2πr*3$$

ratio of costs = $$\frac{S}{C}$$ = $$\frac{4d*2}{2πr*3}$$ = $$\frac{4*r\sqrt[]{π}*2}{2πr*3}$$ = $$\frac{4}{3\sqrt[]{π}}$$

E
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Re: Two plots, one square and the other, circular, were equal in areas.   [#permalink] 24 Jan 2019, 11:31
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