Two sets, A and B, have the same number of elements and the same median. Which set has the higher average?

(1) In Set A, 75% of the numbers are greater than or equal to the median. In Set B, 50% of the numbers are greater than or equal to the median.

The above question is from

MGMAT flashcard of word translation section.

The question is for revision purpose and statement 2 is not given,

The above statement is insufficient to answer a question.

i dint understood an explanation given in flashcard.

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Just think about the question. What is the median ? If you arrange the number in ascending or descending order than the middle number gives the median.

Statement A says 75% of the numbers are greater than or equal too to the median. This means 3/4 of the numbers are equal to the median. Their is no way that 75% can be > the median because than that number is not the median. So this set is something like :

{4,5,5,5} -> median is 5 or {-1,2,2,10} median is 2.

Now Set B is something

Set B

2,4,6,10 -> median is 5 same as above or {0,1,3,4} - median is 2.

Now Avg in set B is greater than Avg in Set A. However Avg in Set A > Avg in set B for the 2nd case.

Hence, one cannot determine whose average is more than the other.