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# Two water tanks, X and Y, were drained simultaneously. If X

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Joined: 02 Mar 2004
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Two water tanks, X and Y, were drained simultaneously. If X [#permalink]

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09 May 2004, 10:53
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Two water tanks, X and Y, were drained simultaneously. If X contains 30 more gallons of water than Y, and both tanks became empty at the same time, how long did it take the tanks to empty?

1. For every gallon drained from Y, 2 gallons drained from X.
2. Tank Y was drained at a constant rate of 20 gallons per hour.

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Joined: 30 Oct 2003
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09 May 2004, 11:51
C it is.
From stem X = Y + 30

A) We dont know rate at which Y is drained.
B) We know rate of Y but not the rate of X
Combine and you get
20 * T = Y and X = 2 * 20 * T
40T = 20T+30 so T = 1.5 hours

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Joined: 07 May 2004
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Location: Ukraine, Russia(part-time)

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11 May 2004, 00:53
hallelujah1234 wrote:
Two water tanks, X and Y, were drained simultaneously. If X contains 30 more gallons of water than Y, and both tanks became empty at the same time, how long did it take the tanks to empty?

1. For every gallon drained from Y, 2 gallons drained from X.
2. Tank Y was drained at a constant rate of 20 gallons per hour.

X = Y + 30,

Tx = Ty,

X/Vx = Y/Vy

1. Vx/Vy = 2

2. Vy = 20.

So, neither 1 nor 2 alone is sufficient, but together 1 and 2 are sufficient.

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Re: DS-99   [#permalink] 11 May 2004, 00:53
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# Two water tanks, X and Y, were drained simultaneously. If X

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