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Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi

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Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi  [#permalink]

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New post Updated on: 17 Feb 2019, 02:27
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Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Ming also mows lawns at a constant rate. How much less time would it take Tyra and Ming working together to mow 3 lawns?

1) Both Tyra and Ming mow lawns at the same rate.

2) It takes Tyra twice as long to mow a lawn as it takes Tyra and Ming working together to mow a lawn.

Originally posted by sameer986 on 17 Feb 2019, 00:39.
Last edited by Bunuel on 17 Feb 2019, 02:27, edited 1 time in total.
Renamed the topic.
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Re: Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi  [#permalink]

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New post 17 Feb 2019, 10:06
Each statement is sufficient to answer the question. My answer is (D).
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Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi  [#permalink]

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New post 17 Feb 2019, 11:14
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Given:: rate of Tyra = \(\frac{3}{2}\) and time of Tyra = 2

Statement 1: rate of Tyra = rate of Ming = \(\frac{3}{2}\)
so (rate of Tyra + rate of Ming) * Time of Both = 3 lawns
\(\frac{6}{2}\) * (time of both) = 3
Time of both = 1 hour
so the difference is 2 - 1 = 1 hour. --> sufficient

Statement 2: (time of Tyra) = 2 (time of both) = 2 hours
so (time of both) = \(\frac{2}{2}\) = 1 hour
so the difference is 2 - 1 = 1 hour. --> sufficient.

so D.
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Re: Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi  [#permalink]

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New post 17 Feb 2019, 11:45
Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Ming also mows lawns at a constant rate. How much less time would it take Tyra and Ming working together to mow 3 lawns?

1) Both Tyra and Ming mow lawns at the same rate.

2) It takes Tyra twice as long to mow a lawn as it takes Tyra and Ming working together to mow a lawn.

rate of tyra=2/3 (two lawn per three hours)
rate of ming=?

to find how much less time will both take to mow 3 lawns than tyra, we will need ming's rate.
1) rate of tyra and ming are same thus rate of ming=2/3 so we do 2/3+2/3=4/3 then 4/3-2/3 gives solution so 1 is sufficinet

2)time tyra takes is twice than tyra and ming together then again by algebra we can get rate of ming's and so it is also sufficinet

Option D is correct. both are sufficinet independently.
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Re: Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi   [#permalink] 17 Feb 2019, 11:45
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Tyra mows lawns at a constant rate. She can mow 3 lawns in 2 hours. Mi

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