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# v = A. 8 + 3v7 B. 4 + 3v7 C. 8 D. 4 E. v7 v- sqrt

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Manager
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v = A. 8 + 3v7 B. 4 + 3v7 C. 8 D. 4 E. v7 v- sqrt [#permalink]

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30 May 2007, 07:55
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v[2v63 + 2/(8+3v7)] =

A. 8 + 3v7
B. 4 + 3v7
C. 8
D. 4
E. v7

v- sqrt
VP
Joined: 08 Jun 2005
Posts: 1145
Followers: 7

Kudos [?]: 213 [0], given: 0

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30 May 2007, 08:42

v[2v63 + 2/(8+3v7)]
v[2v63 + 2/(8+v63)]
v[2v63*(8+v63)/(8+v63) + 2/(8+v63)]
v[(2v63*(8+v63)+2)/(8+v63)]
v[(16v63+2*63)+2)/(8+v63)]
v[(16v63+128)/(8+v63)]
v[16(v63+8)/(8+v63)]
v[16]
4

Senior Manager
Joined: 11 Jun 2006
Posts: 254
Followers: 3

Kudos [?]: 11 [0], given: 0

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30 May 2007, 09:16
I just estimated the value of v7 to be 2.6 and solved from there. The answer was approx. 4, so I put that as the answer.

Does anyone else use this method? I'll only use it when the answer choices are as spaced out as far as they are in this problem.
VP
Joined: 08 Jun 2005
Posts: 1145
Followers: 7

Kudos [?]: 213 [0], given: 0

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30 May 2007, 09:27
baer wrote:
I just estimated the value of v7 to be 2.6 and solved from there. The answer was approx. 4, so I put that as the answer.

Does anyone else use this method? I'll only use it when the answer choices are as spaced out as far as they are in this problem.

I guess there isn't a "correct" way to solve this problem. whatever gives you the correct solution is OK !! your way is faster then mine !!

Senior Manager
Joined: 11 Jun 2006
Posts: 254
Followers: 3

Kudos [?]: 11 [0], given: 0

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30 May 2007, 09:34
I try to use whatever method is faster, but most importantly least prone to error... when estimating, you need to make sure your calculations and assumptions are 100% correct, or it will really throw you off base.
30 May 2007, 09:34
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