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# value of sqrt(x^2) ?

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Joined: 28 Jul 2004
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Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth

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26 Mar 2009, 14:06
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How is sqrt(x^2) = +x or -x ? In other words , why is sqrt(x^2) = |x|?

What if x^2 = 4 and x=-2 --> sqrt (x^2) = sqrt(-2 x -2) = -2 which is != |x|

I am confused on this. Could someone explain please ??
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kris

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Re: value of sqrt(x^2) ? [#permalink]

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27 Mar 2009, 08:43
Didn't you answer your own question . To put in a different perspective.

sqrt of any square is either a positive or negative value of the square.

so sqrt(4) = 2 or -2 as 2^2 = 4 and (-2)^2 is also equal to 4.

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Kudos [?]: 96 [0], given: 24

Re: value of sqrt(x^2) ?   [#permalink] 27 Mar 2009, 08:43
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# value of sqrt(x^2) ?

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