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Venn Diagram Question

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Intern
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Joined: 20 May 2009
Posts: 1

Kudos [?]: [0], given: 0

Venn Diagram Question [#permalink]

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New post 20 May 2009, 07:01
Of the 300 patients who suffered from at least one symptom of A, B, and C, 35% sufffered from A, 45% suffered from B, 40% suffered from C, 10% suffered from exactly 2 of them. How many people suffered from eactly one symptom?

The answer is 255 but I don't know how to solve this. Appreciate the help.

Kudos [?]: [0], given: 0

Senior Manager
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Joined: 08 Jan 2009
Posts: 324

Kudos [?]: 189 [0], given: 5

Re: Venn Diagram Question [#permalink]

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New post 20 May 2009, 22:19
We know that AuBuC = A + B + C - ( AnB + BnC+ CnB) - 2 ( AnBnC)

So 100 % = 35 + 40 + 45 + - ( 10 ) - 2 ( AnBnC)

So exactly 3 of them AnBnC = 5 % so 5 % of 300 = 15

Exactly two of tem = 300 * 10% = 30

eactly one symptom = 300 - 30 -15 = 255.

Kudos [?]: 189 [0], given: 5

Current Student
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Joined: 25 May 2010
Posts: 50

Kudos [?]: 9 [0], given: 22

Location: Taiwan
Concentration: Operations, International Business
GMAT 1: 720 Q50 V38
GPA: 3.59
WE: Supply Chain Management (Manufacturing)
Re: Venn Diagram Question [#permalink]

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New post 20 Mar 2011, 07:01
tkarthi4u wrote:
We know that AuBuC = A + B + C - ( AnB + BnC+ CnB) - 2 ( AnBnC)

So 100 % = 35 + 40 + 45 + - ( 10 ) - 2 ( AnBnC)

So exactly 3 of them AnBnC = 5 % so 5 % of 300 = 15

Exactly two of tem = 300 * 10% = 30

eactly one symptom = 300 - 30 -15 = 255.


--------------

I'm sorry, but I'm a little confused, where do you get the 2 from 2 ( AnBnC)?
Can someone please explain? Thanks!

Kudos [?]: 9 [0], given: 22

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Manager
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Joined: 05 Jan 2011
Posts: 167

Kudos [?]: 200 [1], given: 8

Re: Venn Diagram Question [#permalink]

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New post 20 Mar 2011, 08:45
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tingjojo wrote:
tkarthi4u wrote:
We know that AuBuC = A + B + C - ( AnB + BnC+ CnB) - 2 ( AnBnC)

So 100 % = 35 + 40 + 45 + - ( 10 ) - 2 ( AnBnC)

So exactly 3 of them AnBnC = 5 % so 5 % of 300 = 15

Exactly two of tem = 300 * 10% = 30

eactly one symptom = 300 - 30 -15 = 255.


--------------

I'm sorry, but I'm a little confused, where do you get the 2 from 2 ( AnBnC)?
Can someone please explain? Thanks!



Have a look at http://gmatclub.com/forum/formulae-for-3-overlapping-sets-69014.html#p522537

Kudos [?]: 200 [1], given: 8

Current Student
User avatar
Joined: 25 May 2010
Posts: 50

Kudos [?]: 9 [0], given: 22

Location: Taiwan
Concentration: Operations, International Business
GMAT 1: 720 Q50 V38
GPA: 3.59
WE: Supply Chain Management (Manufacturing)
Re: Venn Diagram Question [#permalink]

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New post 21 Mar 2011, 02:22
Onell wrote:
tingjojo wrote:
tkarthi4u wrote:
We know that AuBuC = A + B + C - ( AnB + BnC+ CnB) - 2 ( AnBnC)

So 100 % = 35 + 40 + 45 + - ( 10 ) - 2 ( AnBnC)

So exactly 3 of them AnBnC = 5 % so 5 % of 300 = 15

Exactly two of tem = 300 * 10% = 30

eactly one symptom = 300 - 30 -15 = 255.


--------------

I'm sorry, but I'm a little confused, where do you get the 2 from 2 ( AnBnC)?
Can someone please explain? Thanks!



Have a look at http://gmatclub.com/forum/formulae-for-3-overlapping-sets-69014.html#p522537



Thanks a lot!! Kudos to you!

Kudos [?]: 9 [0], given: 22

TOEFL Forum Moderator
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Joined: 16 Nov 2010
Posts: 1589

Kudos [?]: 608 [0], given: 40

Location: United States (IN)
Concentration: Strategy, Technology
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Re: Venn Diagram Question [#permalink]

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New post 22 Mar 2011, 04:07
A + AB + AC + B + BC + C + ABC = 300

A + B + C = ?

A + AB + AC + ABC = 35/100 * 300 = 105

B + BC + AB + ABC = 45/100 * 300 = 135

C + AC + BC + ABC = 40/100 * 300 = 120

AB + BC + AC = 10/100 * 300 = 30







A + B + C + 60 + 3ABC = 360

=> A + B + C + 3ABC = 300

A + B + C + ABC = 300 - 30 = 270

=> ABC = 30/2= 15

So A + B +C = 300 - 30 - 15 = 255

or 2 (A+B+C) = 810 - 300 = 510 => (A+B+C) = 510/2 = 255
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Kudos [?]: 608 [0], given: 40

Re: Venn Diagram Question   [#permalink] 22 Mar 2011, 04:07
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